Which structure is found in all eukaryotic
2 answers:
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Answer:
53.6 grams of silver chloride was produced.
Explanation:
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
Mass of silver nitrate = 50.0 g
Mass of hydrogen chloride = 50.0 g
Mass of silver chloride = x
Mass of nitric acid = 46.4 g
Mass of silver nitrate + Mass of hydrogen chloride =
Mass of silver chloride + Mass of nitric acid
[te]50.0 g+50.0 g=x+46.4 g[/tex]
53.6 grams of silver chloride was produced.
Hello!
A) At pH=1
This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to CH₃COOH
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the left)
The chemical structure for CH₃COOH is the first one in the attached images.
B) At pH=7
This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to CH₃COO⁻
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the right)
The chemical structure for CH₃COO⁻ is the second one in the attached images.
Have a nice day!
A) At pH=1
This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to CH₃COOH
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the left)
The chemical structure for CH₃COOH is the first one in the attached images.
B) At pH=7
This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to CH₃COO⁻
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the right)
The chemical structure for CH₃COO⁻ is the second one in the attached images.
Have a nice day!