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GaryK [48]
3 years ago
9

If 1 box cost rs 45 find the cost of 9 boxes​

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

9 boxes cost Rs 405

Step-by-step explanation:

1 box costs 45.

so, how much are 2 boxes ? what do you think ?

right, twice as much : 2 × 45 = 90

how much are 3 boxes ?

now it is three times the cost of 1 box : 3 × 45 = 135

do you see the pattern ?

it is really simple.

that is also the origin why we describe a multiplication by "times". we take a single item so and so many times.

when you see something like this, you know, they are talking about multiplication.

so, here we want to know how much 9 boxes cost.

therefore,

9 × 45 = 405

is the answer.

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MaRussiya [10]

Times then all and get back with me honey


7 0
3 years ago
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5. If "h" is positive how does the parabola move? If negative?
Paul [167]

Answer: positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

Step-by-step explanation: Note that the value for h is subtracted from x, and then this difference is squared. See that positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

7 0
3 years ago
The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
brilliants [131]

Answer:

(a) 11.25 and 1.68  

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 15

             r = number of success

             p = probability of success which in our question is % of cases in

                  which customer problems are resolved on the same day, i.e.;75%

So, here X ~ Binom(n=15,p=0.75)

(a) Expected number of problems to be resolved today = E(X)

            E(X) = \mu = n * p = 15 * 0.75 = 11.25

    Standard deviation = \sigma = \sqrt{n*p*(1-p)} = \sqrt{15*0.75*(1-0.75)} = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

     P(X = 10) = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}

                    = 3003*0.75^{10} *0.25^{5} = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

    = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}

    = 3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4} = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

    given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)  

= \binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}

= 1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}

= 0.6865

3 0
3 years ago
3/4 yard long and 1/2 yard tall what is the area of the poster frame
zmey [24]
The area is 3/8 yd².

Area = length x width

Given:
length = 3/4 yard
width = 1/2 yard

Area = 3/4 yd * 1/2 yd
Area = 3*1/4*2
Area = 3/8 yd²

In multiplying fractions, multiply the numerators, then, multiply the denominators. lastly, simplify the fraction. 3/8 yd² is already in its simplest form.
3 0
3 years ago
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10. The bill (including parts and labor) for the repair of an oven was $142. The cost
Lubov Fominskaja [6]

Total cost=$142

cost of parts=$62

cost paid for labour=$142-$62=$80

According to question,

》cost of labour per hr=$32

which can be written as,

》cost of labour/time=$32

Use cross multiplication,

》time=cost of labour/32

Since cost of labour is 80,

Time=80/32

=2.5hrs

6 0
3 years ago
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