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bonufazy [111]
3 years ago
14

Butane is used as a fuel in camping gas stoves.100 cm3 of butane is burned in excess oxygen .calculate the volume of carbon diox

ide produced at r.t.p
Chemistry
1 answer:
dybincka [34]3 years ago
5 0

The given for the problem:

100 cm^3 butane

Get first the molecular formula of butane and it is C4H10

 

To solution for the problem is:

<span>2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
n = V/22.4</span>

<span>
n (C4H10) = 0.1/22.4 = 0.0047 mol</span>

<span>
n (CO2) = 4 · n (C4H10) = 4 · 0.0047 = 0.018 mol</span>

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Propane gas reacts with oxygen according to this balanced equation: C subscript 3 H subscript 8 space (g )space plus space 5 spa
Misha Larkins [42]

Explanation:

The balanced chemical equation of the reaction is:

C_3H_8(g)+ 5O_2 (g)->3CO_2(g)+4H_2O(g)

From the balanced chemical equation,

1 mole of propane forms ------ 3 mol. of CO_2 gas.

The molar mass of propane is 44.1 g/mol.

One mole of any gas at STP occupies --- 22.4 L.

Hence, 44 g of propane forms (3x22.4 L=) 67.2 L of CO2 gas at STP.

Answer:

Thus, 67.2 L of CO2 is formed at STP.

4 0
2 years ago
In compounds,has an oxidation number 1-​
alex41 [277]
Fluorine in compounds is always assigned an oxidation number of -1
5 0
3 years ago
The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +
Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b) The solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

Explanation:

(a)  Chemical equation for the given reaction in pure water is as follows.

           CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)

Initial:                         0            0

Change:                    +x           +x

Equilibm:                   x             x

K_{sp} = 1.2 \times 10^{-6}

And, equilibrium expression is as follows.

          K_{sp} = [Cu^{+}][Cl^{-}]

       1.2 \times 10^{-6} = x \times x

             x = 1.1 \times 10^{-3} M

Hence, the solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b)  When NaCl is 0.1 M,

       CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq),  K_{sp} = 1.2 \times 10^{-6}

   Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq),  K = 8.7 \times 10^{4}

Net equation: CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

               K' = K_{sp} \times K

                          = 0.1044

So for, CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

Initial:                     0.1                 0

Change:                -x                   +x

Equilibm:            0.1 - x                x

Now, the equilibrium expression is as follows.

              K' = \frac{CuCl_{2}}{Cl^{-}}

         0.1044 = \frac{x}{0.1 - x}

              x = 9.5 \times 10^{-3} M

Therefore, the solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

7 0
3 years ago
Neon (Ne) is in group 18. This element
Aleonysh [2.5K]

Answer:

option 3

Explanation:

Neon is one of the noble gases. Noble gases don't react with any element because of their stability. Elements of Group 18 in Periodic Table are inert gases.

8 0
3 years ago
Which of the following elements is a metalloid?
Deffense [45]
The answer to your question would be silicon. I hope this helped!!!
4 0
3 years ago
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