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RUDIKE [14]
3 years ago
15

I need help can someone please do so?

Chemistry
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

0.296 J/g°C

Explanation:

Step 1:

Data obtained from the question.

Mass (M) =35g

Heat Absorbed (Q) = 1606 J

Initial temperature (T1) = 10°C

Final temperature (T2) = 165°C

Change in temperature (ΔT) = T2 – T1 = 165°C – 10°C = 155°C

Specific heat capacity (C) =..?

Step 2:

Determination of the specific heat capacity of iron.

Q = MCΔT

C = Q/MΔT

C = 1606 / (35 x 155)

C = 0.296 J/g°C

Therefore, the specific heat capacity of iron is 0.296 J/g°C

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Consider a 0.12 M solution of a weak polyprotic acid (H2A) with the possible values of Ka1 and Ka2 given here. Calculate the con
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         H2A(aq) + H2O(l)-------->   H3O^+(aq) + HA^-(aq)

I        0.12                                     0                    0

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Ka1= x^2/  0.12 - x  

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          HA^-(aq) + H20(l)    -------> A^-(aq)   + H3O^+

I       0.0034                                  0               0

C       -x                                          + x            +x

E    0.0034 - x                               x                x

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5.0×10^−5 (0.0034 - x ) = x^2

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x^2 + 5.0×10^−5x - 1.7 * 10^-7 = 0

x=0.00039 M

Learn more about the dissociation of a polyprotic acid:brainly.com/question/14481763

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