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RUDIKE [14]
3 years ago
15

I need help can someone please do so?

Chemistry
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

0.296 J/g°C

Explanation:

Step 1:

Data obtained from the question.

Mass (M) =35g

Heat Absorbed (Q) = 1606 J

Initial temperature (T1) = 10°C

Final temperature (T2) = 165°C

Change in temperature (ΔT) = T2 – T1 = 165°C – 10°C = 155°C

Specific heat capacity (C) =..?

Step 2:

Determination of the specific heat capacity of iron.

Q = MCΔT

C = Q/MΔT

C = 1606 / (35 x 155)

C = 0.296 J/g°C

Therefore, the specific heat capacity of iron is 0.296 J/g°C

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Explanation :

<u>For part A :</u>

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Now put all the given values in the above formula, we get:

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<u>For part B :</u>

q=m\times c\times \Delta T

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Now put all the given values in the above formula, we get:

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