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3 years ago

Match these items

2 answers:

4 0

The correct matches are as follows:

1.instantaneous combustion
G.burning

2.mass of substances before and after a reaction is the same
C.Law of Conservation of Matter

3.substances that combine
A.reactants

4. Yields or makes
B.arrow symbol

5.rapid oxidation
F.explosion

6.new substance
D.product

7.slow oxidation
E.rust

Hope this answers the question. Have a nice day.

Fiesta28 [93]3 years ago

4 0

The CORRECT answers are:

Explosion: Instantaneous Combustion

Law of Conservation of Matter : Mass of substances before and after a reaction is the same

Reactants: Substances that combine

Arrow Symbol: Yields

Burning: Rapid Oxidation

Product: New Substance

Rust: Slow Oxidation

Ths are ALL Correct! Enjoy!

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The two main types of weathering are

tester [92]

The two main types of weathering are material and chemical.

Mechanical weathering is the disintegration of rock into smaller and smaller fragments.

Chemical weathering transforms the original material into a substance with a different composition and different physical characteristics.

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3 years ago

Read 2 more answers

Identify which one is the reducing agent in this reaction

Romashka-Z-Leto [24]

Answer:

Na.

Explanation:

The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).

An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.

A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.

For the reaction:

2Na + S → Na₂S.

Na is oxidized to Na⁺ in (Na₂S) (loses 1 electron). "reducing agent".

S is reduced to S²⁻ in (Na₂S) (gains 2 electrons). "oxidizing agent".

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3 years ago

A graduated cylinder is filled to the 40.00-mL mark with a mineral oil. The masses of the cylinder before and after the addition

castortr0y [4]

Answer:

Firstly, Let's experiment this !

Experiment 1 :

159.446g - 124.966g = 34.48g

34.48g = The mass of Mineral oil.

The density of the mineral oil = M/V = 34.48g/40mL = 0.862g/cm³.

Experiment 2 :

124.966 + 18.173 = 143.139 = The mass of solid + cylinder.

124.966 + 50.952 = 175.918 = The mass of solid + cylinder + Mineral water.

175.918 - 143.139 = 32.779 = The mass of added mineral oil.

Explanation:

Now we have to find the volume of the added mineral oil using the density from experiment 1.

V = 32.779g/0.862g/cm³ = 38.02668213mL

Since we found the volume of the solid, we then have to subtract the added mineral oil volume from the total volume from experiment 1.

Volume of solid = 40-38.02668213 = 1.97331787mL

Density of solid = 18.713g/1.97331787mL = 9.483013499g/cm^3

1.97331787 = (4/3)(3.14)r³

1.97331787*(3/4)(3.14) = .4713338861

.4713338861 = r ³

r = 0.7782328425158433

r = 0.78

Now that's our final answer ! r = 0.78

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3 years ago

Octopus and squids breathe through

svet-max [94.6K]

Octopus and squids breathe like fishes they breathe from gills 

so even octopus and squids breathe through gills too.

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3 years ago

A 10.21 mol sample of argon gas is maintained in a 0.7564 L container at 296.9 K. What is the pressure in atm calculated using t

soldi70 [24.7K]

Answer:

The pressure in atm calculated using the van der Waals' equation, is 337.2atm

Explanation:

This is the Van der Waals equation for real gases:

(P + a/v² ) ( v-b) = R .T

where P is pressure

v is Volume/mol

R is the gas constant and T, T° in K

a y b are constant for each gas, so those values are data, from the statement.

[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 24.34 L.atm/mol

0.04181L/mol .P + 10.24 L.atm/mol = 24.34 L.atm/mol

0.04181L/mol .P = 24.34 L.atm/mol - 10.24 L.atm/mol

0.04181L/mol. P = 14.1 L.atm/mol

P = 14.1 L.atm/mol / 0.04181 mol/L

P = 337.2 atm

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3 years ago