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svetoff [14.1K]
2 years ago
6

Identify the atom provided. * Boron Phophorus Sulfer Aluminum

Chemistry
1 answer:
REY [17]2 years ago
3 0

Answer:

3. I think the answer is Sulfer

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How does molarity and molality affect the concentration of a solution<br>explain.
kolbaska11 [484]

Concentration of a solution can be expressed in terms of molarity and molality

Molarity is the number of moles of solute in a liter of a solution.

Molarity (M) = Moles of solute/Volume(litres) of solution

Molality is the number of moles of solute in one kg of the solution

Molality (m) = Moles of solute/Mass (kg) of solution

Therefore if the volume or the mass of the solution is changed this would affect the concentration.

In addition, volume is a quantity which depends on temperature. However, mass is independent of temperature. Therefore any changes in temperature, can also bring about a change in the molarity of the solution.


5 0
3 years ago
What is the reaction scheme for the experiment of synthesis of methyl salicylate
soldier1979 [14.2K]

The methyl salicylate (wintergreen oil) is the methyl ester of salicylic acid.

Methyl salicylate is produced by esterifying salicylic acid with methanol, the reaction scheme is attached to this answer. In the past, it was commonly distilled from the twigs of Betula lenta (sweet birch) and Gaultheria procumbens (eastern teaberry or wintergreen).

3 0
3 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
2 years ago
Be sure to answer all parts.
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Answer:

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6701g has 4 sig figs

560 has 2 sig figs

Explanation:

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Кее<br> 2. How have observations of the natural world helped<br> in the development of calendars?
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