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icang [17]
3 years ago
11

3/4 of the pupils in Year 9 say their favourite colour is red. There are 144 pupils in Year 9. How many students said red is the

ir favourite colour?
Mathematics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

108 students

Step-by-step explanation:

Take the fraction and multiply by the number of students

3/4 *144 =108

108 students

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GrogVix [38]

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Rains and Splash

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ABCD is a parallelogram. Find the measure of ZABC.<br> HELPPP
Lena [83]

Answer:

50°

Step-by-step explanation:

Opposite angels of a parallelogram are congruent to each other.

This means:

<ADC = <ABC

<ADC = 38° + 12°

<ADC = 50°

Since <ADC = <ABC, therefore,

<ABC = 50°

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3 years ago
What is an equation of the line that passes through the points (4, -1) and<br> (-8, –7)?
Andreas93 [3]

Answer:

y=1/2x-3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-7-(-1))/(-8-4)

m=(-7+1)/-12

m=-6/-12

m=1/2

y-y1=m(x-x1)

y-(-1)=1/2(x-4)

y+1=1/2x-4/2

y=1/2x-2-1

y=1/2x-3

5 0
3 years ago
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
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