Ask question

Ask question

All categories

3 years ago

12

The area of a rectangular tabletop is 4 square feet Cassie will cover the tabletop with square tiles that each have an area of 1

square inch
How many tiles does Cassie need to completely cover the tabletop?

1 answer:

expeople1 [14]3 years ago

8 0

12 inches = 1 foot.

144 inches = 1 square foot.

To find 4 square feet, you need to multiply by 4.

144 * 4 = 576

576 inches = 4 square feet

<h2>You need 576 tiles.</h2>

You might be interested in

Mr. Kennedy raise beef cattle the stock tank near the windmill has a diameter of 3 m what it is for the water is 1.5 m deep how

sergeinik [125]

Answer:

10.6

Step-by-step explanation:

radius = 1.5 height = 1.5 so it's 10.6

7 0

3 years ago

What is the product of 6+5i and 4+7i?

Vilka [71]

(6 + 5i)(4 + 7i) = 24 + 42i + 20i + 35i²
= 35i² + 62i + 24

The product of 6+5i and 4+7i is 35i² + 62i + 24.

8 0

3 years ago

PLSSS HELP ME ON THIS

stiks02 [169]

1. True
2. False
3. True
When ordered for location 1, the values are 34,52,85,86,100 with the median is 85 because it is in the middle of the other values. True

The range of location 2 is from 19 to 65 base don data shown, False

The median for location 2 is (20,29) which is smaller than the 85 for location 1 so location 1 had more participants if based on the median measurement. True

3 0

4 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

Choose the function whose graph is given below.

kompoz [17]

Where is the pic?
i need to see it

3 0

3 years ago