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STatiana [176]
3 years ago
12

In a school there are 1800 boys and 1200 girls. In an exam only 32 % of the boys passed and 50 % of the girls passed. Find the p

ercentage of the total who did not pass.​
Mathematics
1 answer:
Alex73 [517]3 years ago
5 0

Answer:

Step-by-step explanation:

The total number of students is 1800 + 1200 =  3000

The % of boys who did not pass is 100% - 32% = 68%

The number of boys who did not pass is 68/100 * 1800 =       1224

The % of the girls who did not pass is 100%  - 50% = 50%

The number of girls who did not pass was 50/100 * 1200 =    600

The total number who did not pass was                                  1824

The % who did not pass was 1824/3000 * 100 = 60.8%

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The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

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44x - 22y = 110

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<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

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140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

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