The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
A
Step-by-step explanation:
-5 i s greater than -2.
Nope that aint true
-2 is greater than -5 is correct since -2 is closer to the postivie numbers and zero.
-5 is farther so it is less than -2.
Answer:
n = 5.4
Step-by-step explanation:
Equation: 4n = 21.6
To solve this equation for n, divide both sides by 4 to get n by itself.
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<u>Step 1: Divide both sides by 4</u>
4 * n / 4 = 21.6 / 4
n = 5.4
Answer: n = 5.4
Answer:
(4, - 1)
(-1, 6)
Step-by-step explanation:
Given the expression :
3x+y<14
Test the opprions to find out the true statement.
(7, - 7)
3(7) + (-7) < 14
21 - 7 < 14
15 < 14 (not true)
(-1, 6)
3(-1) + 6 < 14
3 + 6 < 14
9 < 14 ( true)
(3, 6)
3(3) + 6 < 14
9 + 6 < 14 ( not true)
(4, - 1)
3(4) - 1 < 14
12 - 1 < 14 ( true)
(6,0)
3(6) + 0 < 14
18 < 14 ( not true)
Answer:
Width=37in
Length=55in
Step-by-step explanation:
Let x in be the width dimension, the length dimension will be x+18 in. Area of a rectangle is calculated as A=lw. Given the area as2143 sq in, x can be calculated as:
#Substitute for every x in our function to find the true value of x:
#l=37+18=55in
for x=38:
#l=38+18=56in
For x=39:
#l=39+1854in
From the calculations above, A television with a width of 37 in and length 55in has its area closest to 2143 sq in.
