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3 years ago

Find the length of the hypotenuse in triangles with sides 63m and 2752cm, hypotenuse in metres

Mathematics

2 answers:

qwelly [4]3 years ago

8 0

C² = a² + b²
c² = (63)² + (2752)²
c² = 3969 + 7573504
c² = 7577473
c = 2752.72101747

Ann [662]3 years ago

5 0

The Pythagorean Theorem states that a² + b² = c².

Additionally, the conversion rate of centimetres to meters is 1 meter : 100 centimeters.

Since we're finding the hypotenuse in metres, the first step is to make sure all of our measurements are in the same unit. Following the conversion rate, we'll convert the measurement of 2752 cm into metres.

2752/100 = 27.52m

Now that we know both side lengths, we can use the Pythagorean Theorem to solve for the hypotenuse.

First, we'll substitute in our values for the formula.

(63)² + (27.52)² = c²

Next, we'll square the two values we know.

(3969) + (757.3504) = c²

From there, we'll add the values we know together.

4726.3504 = c²

And finally, we'll find the square root of our current value to find the length of the hypotenuse.

68.7484574372 = c

Rounding our value, we're left with 68.75.

Therefore, the hypotenuse is equal to 68.75m.

Hope this helped! :)

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finlep [7]

If you would like to solve the system of equations, you can do this using the following steps:

-3x + 4y = 12
x * 1/4 - 1/3 * y = 1 ... x * 1/4 = 1 + 1/3 * y ... x = 4 + 4/3 * y
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-3 * (4 + 4/3 * y) + 4y = 12
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-12 - 12 = 0
-24 = 0

The correct result would be: the system of the equations has no solution; the two lines are parallel.

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3 years ago

If the pattern rule is defined by the equation `t = 6n`, where `t` is the term value and `n` is the term number, what is the one

blagie [28]

Answer:

600

Step-by-step explanation:

Given

equation t = 6n

n is term number

we have to find 100th term.

Thus, term number is 100

substituting 100 in place of n in equation t=6n , we can find the value of 100th term

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Thus, 100th term is 600.

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2 years ago

Y=3x+7 solve this system of equation using any method

love history [14]

Answer:

x=2, y=13

Step-by-step explanation:

In order to get this by addition which is the easiest way for this you want to take both equations

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4x+y=21 and 3x-y=-7 It'll look like

4x+y=21

3x-y=-7 add those It will get rid of the y

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3 years ago

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Naily [24]

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3 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

Step-by-step explanation:

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

We know that Quadratic formula is :

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

$x^2 + 20 = 2x$

⇒ $x^2-2x+20=0$

$a=1\\b=-2\\c=20$

Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

⇒ $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

⇒ $x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}$

⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

7 0

3 years ago