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3 years ago

Please I really need help on this

Physics

2 answers:

mylen [45]3 years ago

6 0

It would be that all of the elements in the column have similar chemical properties. I hope that this helped you out hon :)

taurus [48]3 years ago

3 0

The secondgfgghhhhhh

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A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. Wha

gtnhenbr [62]

Answer:

0.0231 m/s

Explanation:

Given the question :

A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. What is his average velocity?

Distance walked south = 2.099 metre

Time taken = 29.01s

Distance walked north = 1.429 metre

Average Velocity = Displacement / time

The Displacement is hence,

(2.099 m - 1.429m) = 0.67m

Average Velocity = 0.67m / 29.01s

Average Velocity = 0.02309 m/s

Average Velocity = 0.0231 m/s

8 0

4 years ago

A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the

ANEK [815]

Answer:

Given: 

m1 = 7 kg

V1 = 12 m/s

m2 = 25 kg

V2 = 6 m/s

To find:

Combined speed of two balls stick together after collision V = ?

Solution:

According to law of conservation of momentum,

m1V1 + m2V2 = (m1+m2)V

7×12 + 25×6 = (7+25)V

84 + 150 = 32V

V = 234/32

V = 7.31 m/s

Combined speed of two ball is 7.31 m/s

Thanks for joining brainly community!

4 0

2 years ago

At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is

MArishka [77]

Answer:

A) F_g = 8.9278 × 10^(-30)

B) F_e = 1.6 × 10^(-17) N upwards

C) F_m = 6.8 × 10^(-17) N downwards

Explanation:

A) Formula for gravitational force is;

F_g = m_e × g

m_e is mass of electron = 9.11 x 10^(-31) kg

F_g = 9.11 x 10^(-31) × 9.8

F_g = 8.9278 × 10^(-30) N downwards

B) Formula for Electric force is;

F_e = qe

q is charge on electron = 1.6 × 10^(-19) C

E is electric field = 100 N/C

F_e = 1.6 × 10^(-19) × 100

F_e = 1.6 × 10^(-17) N upwards

C) Magnetic force is given by the formula;

F_m = qVB

q is charge on electron = 1.6 × 10^(-19) C

V is velocity given as 8.50 × 10^(6) m/s

B is magnetic field = 50.0 μT = 50 × 10^(-6) T

F_m = 1.6 × 10^(-19) × 8.50 × 10^(6) × 50 × 10^(-6)

F_m = 6.8 × 10^(-17) N downwards

6 0

3 years ago

A 755 N box rests on a floor with a coefficient of kinetic friction of 0.600 and a coefficient of static friction of 0.800. What

GrogVix [38]

Answer:

fr = R× co-efficient

= 755 × 0.80

= 604N

Explanation:

4 0

3 years ago

A solid cylinder is mounted above the ground with its axis of rotation oriented horizontally. A rope is wound around the cylinde

Romashka [77]

Answer:

(a)10.5 rad/s2

(b) 20.9 rev

Explanation:

As the block of mass 53 kg is falling and pulling on the rope. The tension force on the rope must be equal to the gravity acting on the block according to Newton's 3rd law

T = mg = 53*9.81 = 519.93 N

Since this tension force would rotate the cylinder freely without any friction. The torque created by this tension force is

To = TR = 519.93 * 0.36 = 187.17 Nm

This solid cylinder would have a moment of inertia around it's rotating axis of:

$I = \frac{mR^2}{2} = \frac{275 * 0.36^2}{2} = 17.82kgm^2$

(a)We can use Newton's 2nd law to calculate the angular acceleration exerted by such torque on the solid cylinder

$\alpha = \frac{To}{I} = \frac{187.17}{17.82} = 10.5 rad/s^2$

(b) With such constant angular acceleration, the angle it would make after 5s is

$\theta = \frac{\alphat^2}{2} = \frac{10.5*5^2}{2} = 131.3 rad$

Since each revolution equals to $2\pi rad$ of angle, we can calculate the number of revolution it makes

$\frac{\theta}{2\pi} = \frac{131.3}{6.28} \approx 20.9 rev$

(c) Assume the thickness of the rope is negligible (and its wounded radius is unchanging), we can calculate the rope length unwinded after rotating 131.3rad

$\theta R = 131.3*0.36 = 47.27 m$

3 0

3 years ago