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Bogdan [553]
3 years ago
9

14. Looking ahead: Give an example of how the Law of Conservation of Energy applies to eating your favorite meal. Give at least

2 energy transformations.(5 pts)
Physics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

The law of conservation of energy applies to eating your favorite food in that the energy contained in the food is being converted to energy usable for the body system after the final digestion(Glucose or simple sugar, amino acid, etc)

Examples of transformation of energy include

(1) Transformation from Chemical energy in battery to light energy in bulb

(2) Transformation of Electrical energy to thermal/Heat energy in electric stove.

Explanation:

The law of conservation of energy states that energy can neither be created or distroy. It can only by converted from one form to another.

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The energy of atoms and molecules in an object due to their motion is_______ energy
QveST [7]
I think the answer is potential 
7 0
3 years ago
In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin
alexandr402 [8]

Answer:

a) v=0.999124c

b) E=7.566*10^{22}

c) E_a=760 times\ larger

Explanation:

From the question we are told that

Distance to Betelgeuse d_b=430ly

Mass of Rocket M_r=20000

Total Time in years traveled T_d=36years

Total energy used by the United States in the year 2000 E_{2000}=1.0*10^20

Generally the equation of speed of rocket v mathematically given by

v=\frac{2d}{\triangle t}

v=860ly/ \triangle t

where

\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\sqrt{(860)^2+(36)^2}

\triangle t=860.7532

Therefore

v=\frac{860ly}{ 860.7532}

v=0.999124c

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2

E=7.566*10^{22}

c)Generally the equation of the energy E_a required to accelerate the rocket mathematically given by

E_a=\frac{E}{E_{2000}}

E_a=\frac{7.566*10^{22}}{1.0*10^{20}}

E_a=760 times\ larger

8 0
3 years ago
Name of compounds<br>a. H2Co3<br>b. NH4OH<br>c.AlPO4<br>d.NaOH<br>e.AuCI3<br>​
seraphim [82]

Answer:

<em><u>a) </u></em><em><u> </u></em><em><u>Carbonic acid</u></em>

<em><u>b</u></em><em><u>)</u></em><em><u> </u></em><em><u>ammonium hydroxide</u></em>

<em><u>c</u></em><em><u>)</u></em><em><u> </u></em><em><u>Aluminum phosphate</u></em>

<em><u>d</u></em><em><u>)</u></em><em><u> </u></em><em><u>Sodium hydroxide</u></em>

<em><u>e</u></em><em><u>)</u></em><em><u> </u></em><em><u>Gold trichloride</u></em>

Explanation:

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3 0
3 years ago
Any of two or more forms of the same element which differ only in the number of neutrons their atoms contain is called an
telo118 [61]
C. isotope

Isotopes have the same atomic number but different mass number because of the difference in the number of neutrons in the nucleus of the atom.
8 0
3 years ago
This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The mag
sweet-ann [11.9K]

Answer:

Explanation:

Given

coefficient of kinetic friction(\mu _k)=0.34

inclination \theta =44

weight of block=51 N

(a) When block is moving upward friction force acts downward

thus

Fsin\theta -W-f_r=0

as block is moving with constant velocity thus F_{net} is zero

f_r=\mu _kN=0.34\times Fcos\theta

F\left ( \sin \theta -\mu \cos \theta \right )=W

F=\frac{51}{0.45}=113.31 N

(b)When Block slides down the wall friction changes its direction to oppose the block

Fsin\theta -W+f_r=0

F\left ( \sin \theta +\mu \cos \theta \right )=W

F=\frac{W}{\left ( \sin \theta +\mu \cos \theta \right )}

F=\frac{51}{0.939}=54.299 N

3 0
4 years ago
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