. An iron cube (ρ = 7860 kg/m3) having sides of 1 cm is submerged in open fresh water (ρ = 1000kg/m3) with its top surface at a

Question

3 years ago

8

. An iron cube (ρ = 7860 kg/m3) having sides of 1 cm is submerged in open fresh water (ρ = 1000kg/m3) with its top surface at a

depth of 2.5 m. Considering that its top surface is held horizontal with respect to the water surface, determine the difference in pressure between the top and bottom surfaces of the cube?

Physics

1 answer:

Korolek [52] · Answer 1 · 2022-02-15T04:29:10+03:00

Korolek [52]3 years ago

5 0

Answer:

$\Delta P = 98.07\,Pa$

Explanation:

The difference between top and bottom surfaces is computed by the following hydrostatic equivalence:

$\Delta P = \rho_{w}\cdot g \cdot \Delta h$

$\Delta P = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.01\,m)$

$\Delta P = 98.07\,Pa$