Answer
given,
flow rate = p = 660 kg/m³
outer radius = 2.8 cm
P₁ - P₂ = 1.20 k Pa
inlet radius = 1.40 cm
using continuity equation
A₁ v₁ = A₂ v₂
π r₁² v₁ = π r₁² v₂



Applying Bernoulli's equation





v₂ = 1.97 m/s
b) fluid flow rate
Q = A₂ V₂
Q = π (0.014)² x 1.97
Q = 1.21 x 10⁻³ m³/s
Answer:
If the ship speed is doubled, then the power developed is 8 times the initial value.
Explanation:
ship power is roughly proportional to the cube of the speed, so
P ∝ v³
If the speed is doubled, then the power developed becomes
P ∝ (2)³ = 8 times
Therefore, if the ship speed is doubled, then the power developed is 8 times the initial value.
Answer:
c
motorcycle, telephone, piano, lawn mower
The solution for this problem is:
For 1st minimum, let m be equal to 1.
d = slit width
D = screen distance.
Θ = arcsin (m * lambda/ (d))
= 0.13934 rad, 7.9836 deg
y = D*tan (Θ)
y = 6.50 * tan (7.9836)
= 0.91161 m is the distance from the central maximum to the first-order minimum
Answer:
Low Potential energy and High Kinetic energy
Explanation:
Hope this helps and have a good day! Apologies if it's wrong.<3