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Mumz [18]
3 years ago
8

Ammonia is a weak base. if the initial concentration of ammonia is 0.150 m and the equilibrium concentration of hydroxide is 0.0

016m, calculate kb for ammonia.
Chemistry
1 answer:
NARA [144]3 years ago
7 0
Answer is: Kb for ammonia is 1.73·10⁻⁵.<span>
Chemical reaction of ammonia in water: NH</span>₃ + H₂O → NH₄⁺ + OH⁻<span>.
Kb(NH</span>₃) = ?<span>.
c</span>₀(NH₃<span>) = 0.150 M.
c(NH</span>₄⁺) = c(OH⁻<span>) = 0.0016 M.
c(NH</span>₃<span>) = 0.150 M - 0.0016.
</span>c(NH₃) = 0.1484 M.<span>
Kb</span>(NH₃) = c(NH₄⁺) · c(OH⁻) / c(NH₃<span>).
Kb</span>(NH₃) = (0.0016 M)² / 0.1484 M.
Kb(NH₃) = 1.73·10⁻⁵.<span>

</span>
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A mixture of 50.0 mL of ammonia gas and 60.0 mL of oxygen gas react. If all the gases are at the same temperature and pressure,
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Answer:

72.0 mL of steam is formed.

Explanation:

The reaction is :

4 NH_{3} + 5O_{2} \rightarrow 4NO+6H_{2} O

You can treat coefficient of compounds as amount of volume used.

Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.

For 1 mL of ammonia \frac{5}{4} (=1.25) mL of oxygen is used to form \frac{4}{4} (=1) mL of nitric oxide gas and \frac{6}{4} (=1.5) mL of steam.

OR

Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of NH_{3} become one like this

NH_{3} + \frac{5}{4} O_{2} \rightarrow \frac{4}{4}NO+\frac{6}{4}H_{2} O

We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :

<em>1.  </em><em>Assume ammonia to be completely exhausted</em>

For 50 mL of ammonia 50 \times \frac{5}{4} (= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.

2.  <em>Assume oxygen to be completely exhausted</em>

For 60 mL of oxygen only 60 \times \frac{4}{5} (=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.

60\times\frac{4}{5}NH_{3} + 60\ O_{2} \rightarrow 60\times\frac{4}{5}NO+60\times\frac{6}{5}H_{2} O\\\\48NH_{3} + 60\ O_{2} \rightarrow 48NO+72H_{2} O

Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form 60 \times \frac{4}{5} (= 48) mL of nitic oxide gas and 60 \times \frac{6}{5} (= 72) mL of steam.

Therefore <em>72 mL of steam </em>is formed.

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The question is incomplete, this is the complete question;

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(c) The substance boils at 1105 ∘C.

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(h) The substance is a good conductor of electricity.

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(a) Physical

(b) Physical

(c) Physical

(d) Physical

(e) Chemical

(f) Chemical

(g) Physical

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(e) The substance burns in air, producing an intense white light. Burning is a chemical change. It is a reaction of a substance with oxygen

(f) The substance reacts with chlorine to give a brittle white solid. This is a chemical reaction as the question says.

(g) The substance can be pounded into thin sheets or drawn into wires. Ductility is a physical change, the substance remains chemically unchanged

(h) The substance is a good conductor of electricity. Any conductivity is physical, the substance remains chemically unchanged

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