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Mumz [18]
3 years ago
8

Ammonia is a weak base. if the initial concentration of ammonia is 0.150 m and the equilibrium concentration of hydroxide is 0.0

016m, calculate kb for ammonia.
Chemistry
1 answer:
NARA [144]3 years ago
7 0
Answer is: Kb for ammonia is 1.73·10⁻⁵.<span>
Chemical reaction of ammonia in water: NH</span>₃ + H₂O → NH₄⁺ + OH⁻<span>.
Kb(NH</span>₃) = ?<span>.
c</span>₀(NH₃<span>) = 0.150 M.
c(NH</span>₄⁺) = c(OH⁻<span>) = 0.0016 M.
c(NH</span>₃<span>) = 0.150 M - 0.0016.
</span>c(NH₃) = 0.1484 M.<span>
Kb</span>(NH₃) = c(NH₄⁺) · c(OH⁻) / c(NH₃<span>).
Kb</span>(NH₃) = (0.0016 M)² / 0.1484 M.
Kb(NH₃) = 1.73·10⁻⁵.<span>

</span>
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Glucose, C6H12O6,C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the eq
Ilia_Sergeevich [38]

Answer:

Mass of oxygen = 61.824 g

Mass of carbon dioxide = 85.01 g

Explanation:

Given data:

Mass of glucose = 58 g

Mass of carbon dioxide = ?

Mass of oxygen = ?

Solution:

First of all we will write the balanced chemical equation,

C₆H₁₂O₆  + 6O₂       →    6CO₂  + 6H₂O

Moles of glucose:

Number of moles = mass / molar mass

Number of moles = 58 g/180 g/mol

Number of moles =  0.322 mol

Now we compare the moles of oxygen with glucose from balance chemical equation.

                             C₆H₁₂O₆          :              O₂  

                                    1                :              6

                                    0.322       :              0.322×6 = 1.932 mol

Mass of oxygen:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  1.932 mol × 32 g/mol

Mass of oxygen =  61.824 g

Now we compare the moles of carbon dioxide with moles of glucose and oxygen.

                              C₆H₁₂O₆            :              CO₂

                                   1                   :                 6

                                  0.322           :           0.322×6 = 1.932 mol

                                   

                                 O₂                    :                 CO₂

                                  6                     :                  6

                                 1.932                :                  1.932

Mass of carbon dioxide;

mass of carbon dioxide = number of moles × molar mass

mass of carbon dioxide =  1.932 mol × 44 g/mol

mass of carbon dioxide =  85.01 g

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4 years ago
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Explanation:

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