Answer:
0.228 mol FeO
Explanation:
2FeS2 + 5 O2----> 2FeO + 4SO2
from reaction 5 mol 2 mol
given 0.57 mol x
x = 0.57*2/5 = 0.228 mol FeO
its B on plato .. ... . .. . . . . . . ..
We need to set up an I.C.E chart as follows:
CO H20 CO2 H2
<span>I 0.35 0.40 0 0 </span>
<span>C .35-x 0.40-x x x </span>
<span>E 0.19 0.40-x x x
</span>
We have 0.35 mol of CO at the start and 0.19 remaining. This means that x=0.35-0.19 >> 0.16
<span>Now substitute in 0.16 in your Ke equation. </span>
<span>Just in case you're having trouble with that: </span>
<span>Kb= [Products]/[Reactants] = ([CO][H2O])/([CO2][H2])
</span>
Therefore, the constant of equilibrium would be equal to 0.56.
<h2><u>Full Question: </u></h2>
Attached in attachment.
<h2><u>Answer</u>:</h2>
Y is from Group 17. It needs 1 electron to complete its octet. There are total 6 lone pairs in molecule and 1 bond pair. The bond is covalent bond.
<h3><u>Explanation</u>:</h3>
In the picture given, we can see that it contains Lewis Dot structure of two elements X and Y. The X is said as a halogen and also correspondingly has 7 electrons in its outermost shell. The Y isn't mentioned which element it is, but similarly to X it also has 7 electrons in its outermost shell. So it is also a halogen. The group of the halogen is group 17. So Y belongs to group 17.
As the element has 7 electrons in its outermost shell, so it needs 1 electron to fulfill it's octet. It forms a covalent bond with X from where it gets 1 electron via sharing.
So now, there are three unshared electron pair of X and 3 unshared electron pair of Y. So a total of 6 unshared electron pair and 1 bond pair of electron between X and Y.
Answer:
0.0063 mol
Explanation:
Step 1: Write the balanced combustion equation
C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(g)
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₈H₁₈ to CO₂ is 1:8.
Step 3: Calculate the number of moles of C₈H₁₈ needed to produce 0.050 moles of CO₂
0.050 mol CO₂ × 1 mol C₈H₁₈/8 mol CO₂ = 0.0063 mol C₈H₁₈