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velikii [3]
2 years ago
7

Name the compounds represented by the

Chemistry
1 answer:
katen-ka-za [31]2 years ago
7 0

Answer:

Canxi nito dioxit; Sắt oxit vàng; Amoni dicromat;đồng axitaxetic

Explanation:

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A sample of the chiral molecule limonene is 62% enantiopure. what percentage of each enantiomer is present? what is the percent
ikadub [295]

The mixture contains 62 % one isomer and 38 % the enantiomer.

Let’s say that the mixture contains 62 % of the (<em>R</em>)-isomer.

Then % (<em>S</em>) = 100 % -62 % = 38 %

ee = %  (<em>R</em>) - % (<em>S</em>) = 62 % -38 % = 24 %


6 0
2 years ago
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Why did the Mars Climate Orbiter crash?
IRISSAK [1]

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<h3> The Mars Climate Orbiter crashed, because of a navigation error, and a futile to convert english units to metric units.</h3>

4 0
2 years ago
Silver nitrate and calcium chloride react to form calcium nitrate and silver chloride. Write the equation.
8090 [49]

Answer:

Explanation:

2AgNO3 + CaCl2 ----> 2AgCl +  Ca(NO3)2

6 0
3 years ago
Which correctly describes the relationship between genes and chromosomes?​
Vlada [557]

Answer:

Chromosomes are structures within cells that contain a person's genes.

Explanation:

Genes are segments of deoxyribonucleic acid (DNA) that contain the code for a specific protein that functions in one or more types of cells in the body. Chromosomes are structures within cells that contain a person's genes. Genes are contained in chromosomes, which are in the cell nucleus.

6 0
2 years ago
(C6H6) can be biodegraded by microorganism. if 30 mg of benzene is present, what amount of oxygen required for biodegradation, n
quester [9]

Answer:

36.92 mg of oxygen required for bio-degradation.

Explanation:

5C_6H_6+15O_2\rightarrow 12CO_2+15H_2O

Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )

Moles benzene =\frac{0.03 g}{78 g/mol}=0.0003846 mol

According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.

Then 0.0003846 mol of benzene will react with:

\frac{15}{5}\times 0.0003846 mol=0.0011538 mol of oxygen gas

Mass of 0.0011538 moles of oxygen gas:

0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg

36.92 mg of oxygen required for bio-degradation.

4 0
2 years ago
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