Answer:
The frequency of photon is 0.75×10¹⁵ s⁻¹.
Explanation:
Given data:
Energy of photon = 5×10⁻¹⁹ J
Frequency of photon = ?
Solution:
Formula;
E = hf
h = planck's constant = 6.63×10⁻³⁴ Js
5×10⁻¹⁹ J = 6.63×10⁻³⁴ Js ×f
f = 5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js
f = 0.75×10¹⁵ s⁻¹
The frequency of photon is 0.75×10¹⁵ s⁻¹.
Answer:
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- <u><em>C) How much energy was added to the substance to increase molecule motion? </em></u>
Explanation:
<em>The most relevant question to ask regarding this change</em> must take into account the physical knowledge about matter.
When matter changes from<em> liquid </em>state to <em>gaseous</em> state, a physical change called evaporation, the particles (molecules or atoms) of the <em>pure substance </em>will separate from each other, take up more space and move faster.
<em>Condensation</em> is the opposite to evaporation, thus the option A) is not the most relevant question.
<em>The charge of the particles</em> does not change; so the option B) is not relevant at all.
The particles should gain energy from the surroundings to <em>increase</em> their <em>motion</em> (kinetic energy) when they pass from liquid state, where they move slower, to gas state, where they move faster. Hence, the option<em> C), How much energy was added to the substance to increase molecule motion?</em> , is totally relevant.
Since this is an increase in the <em>kinetic energy of the molecules</em>, the option D) is not relevant.
Answer:
that would be true you place it outside the hexagon
Explanation:
The equilibrium reaction is
2 NOBr ⇄ 2 NO + Br₂
The initial molarity of NOBr is 0.174 mol/1 L = 0.174 M. Let's apply the ICE approach which stands for Initial-Change-Equilibrium.
2 NOBr ⇄ 2 NO + Br₂
I 0.174 0 0
C -2x +2x +x
----------------------------------------------------
E 0.174-2x 2x x
Since E for Br₂ is 1.79*10⁻² M, then that means x = 1.79*10⁻² M. We can compute E for the other compounds.
E for NOBr = 0.174 - 2(1.79*10⁻²) = 0.1382 M
E for NO = 2(1.79*10⁻²) = 0.0358 M
The expression for Kc according to the reaction is:
Kc = [NO]²[Br₂]/[NOBr]²
Kc = [0.0358]²[1.79*10⁻²]/[0.1382]²
<em>Kc = 1.2×10⁻³</em>
When the parallel light rays exit a convex lens, it comes away or diverge.