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1. The calendar below shows a sample month of the year. Suppose that you see a full moon on the first day of this month.

1 answer:

Anuta_ua [19.1K]2 years ago

6 0

Answer:The 1st Quarter Moon is a primary Moon phase when we can see exactly half of the Moon's surface lit up. ... The First Quarter Moon rises around midday and is visible in the day sky. ... when the Moon has reached the first quarter of its orbit around Earth, hence the name. ... Full Moon Names · Taking pictures of the Moon.

Explanation:

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How much (mL) of a 2.0 M sodium hydroxide solution would it take to neutralize 50 mL of a 6.0 M solution of hydrochloric acid?

Tom [10]

Answer:

150ml

Explanation:

For this question,

NaOH completely dissociates. It is a strong base

HCl also completely dissociates. It is a strong acid

So we have this equation

m1v1 = m2v2 ----> equation 1

M2 = 2m

V1= ??

M2 = 6m

V2 = 50m

When we input these into equation 1, we have:

2m x v1 = 6m x 50ml

V1 = 6m x 50ml/2

V1 = 300/2

V1 = 150ml

Therefore NaOH that is required to neutralize the solution of hydrochloric acid is 150ml.

Thank you

8 0

2 years ago

We make observations with our five senses to help us identify things. Can you identify this living thing, using the key and the

tigry1 [53]

Answer:

The question you have provided is incomplete

Explanation:

6 0

2 years ago

If the human body contains about 50 deciliters of blood, and the blood has about 15 grams of hemoglobin per deciliter, and all o

Tcecarenko [31]

Answer:

The blood will contain 750 grams of O2

Explanation:

Volume of blood in the human body = 15 deciliters

Mass of hemoglobin per deciliter of blood = 15 grams

Mass of hemoglobin in 50 deciliters of blood = 50×15 = 750 grams

Since all the hemoglobin molecules are saturated with O2, mass of O2 in the blood will be the same as mass of hemoglobin molecules in the blood.

Therefore, mass of O2 in the blood is 750 grams

6 0

2 years ago

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In 1938, Otto Hahn and Fritz Strassman discovered that uranium nuclei could spit and form smaller nuclei, or different elements.

ehidna [41]

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8 0

2 years ago

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Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus

alex41 [277]

Answer: 35.4 g

Explanation:

The balanced reaction is :

$2P+3Cl_2\rightarrow 2PCl_3$

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of phosphorous}=\frac{15.5g}{31g/mol}=0.50moles$

$\text{Moles of phosphorous chloride}=\frac{50.9g}{137g/mol}=0.372moles$

$2P+3Cl_2\rightarrow 2PCl_3$

According to stoichiometry :

2 moles of phosphorous chloride are produced by = 3 moles of $Cl_2$

Thus 0.37 moles of phosphorous chloride are produced by= $\frac{3}{2}\times 0.372=0.558moles$ of $Cl_2$

Mass of $Cl_2=moles\times {\text {Molar mass}}=0.558moles\times 71g/mol=35.4g$

Thus 35.4 g of chlorine reacted with the phosphorus

5 0

2 years ago

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