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2 years ago

1. The calendar below shows a sample month of the year. Suppose that you see a full moon on the first day of this month.

Chemistry

1 answer:

Anuta_ua [19.1K]2 years ago

6 0

Answer:The 1st Quarter Moon is a primary Moon phase when we can see exactly half of the Moon's surface lit up. ... The First Quarter Moon rises around midday and is visible in the day sky. ... when the Moon has reached the first quarter of its orbit around Earth, hence the name. ... Full Moon Names · Taking pictures of the Moon.

Explanation:

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PLS HELP QUICK ALOTTT OF POINTS

timofeeve [1]

Answer:

$\boxed {\boxed {\sf 0.80 \ mol\ F}}$

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

$\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

$4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

Flip the ratio so the units of atoms of fluorine cancel each other out.

$4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}$

$4.8 \times 10^{23} *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }$

Condense into 1 fraction.

$\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F$

Divide.

$0.7970773829 \ mol \ F$

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

$0.80 \ mol \ F$

4.8 × 10²³ fluorine atoms are equal to <u>0.80 moles of fluorine.</u>

6 0

2 years ago

Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=−2043 kJ

Leokris [45]

Given teh equation adn the heat of reaction, reaction 2's heat of reaction can be obtained by simply multiplying teh heat of reaction of 1 by 3. The final answer is -6129 kJ.

6 0

2 years ago

To what Kelvin temperature must a balloon

snow_tiger [21]

Answer:

$T_2=261.46\ K$

Explanation:

It is given that,

Original temperature, $T_1=323^{\circ}C=596.15\ K$

Original volume, $V_1=2.85\ L$

We need to find the temperature if the volume of the balloon to be shrink to 1.25 L.

According to Charles law, at constant pressure, $V\propto T$

It would means, $\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

T₂ = ?

$T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1.25\times 596.15}{2.85}\\\\T_2=261.46\ K$

So, the new temperature is 261.46 K.

4 0

2 years ago

I need help pleasee

Readme [11.4K]

Answer:

Explanation:

6. Where on the graph does adding heat energy NOT raise the temperature?

What is the heat energy DOING if it's not raising the temperature? :its being compressed I believe its vaporizing

7. What is temperature A called? Freezing

8. What is temperature B called? Vaporizing

4 0

2 years ago

A liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 93.0 mL

shutvik [7]

Answer:

Mass of solid = 189.141 gram

Explanation:

Given:

Total volume = 93 ml

Mass of liquid = 33.7 gram

Density of liquid = 0.865 g/ml

Density of solid = 3.50 g/ml

Find:

Mass of solid = ?

Computation:

Volume of liquid = Mass of liquid / Density of liquid

Volume of liquid = 33.7 / 0.865

Volume of liquid = 38.9595 ml

Volume of solid = Total volume - Volume of liquid

Volume of solid = 93 - 38.9595

Volume of solid = 54.0405 ml

Mass of solid = Volume of solid × Density of solid

Mass of solid = 54.0405 ml × 3.50 g/ml

Mass of solid = 189.141 gram

7 0

3 years ago