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3 years ago

Which statements describe prominences? Check all that apply.

Chemistry

2 answers:

ella [17]3 years ago

7 0

Answer:

B. Prominences are composed of cool, dense gas.

C. Prominences can disturb radio communications on Earth.

D. Prominences cycle over an 11-year period.

E. Prominences are loop shaped.

Explanation:

Prominence is the release of high energy particles or dense gases in the form of a loop shape from the surface of the sun. It is cooler and flows out into the Sun's hot atmosphere known as corona.

Once formed, prominence can be quiescent in the space for some period of time before it erupt and get ejected. This eruption and ejection can lead to coronal mass ejections which extends over a very long distance.

When compared to the Sun's temperature, prominences are cooler.

tino4ka555 [31]3 years ago

4 0

Answer:

B, C, E

Explanation:

I just did it on edge 2020

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Define saturated and unsaturated fats

Sphinxa [80]

Answer:

<h3><u>Saturated and unsaturated</u>:-</h3>

Are a form of fat in which all or most of the fatty acid chains are single bonds. Glycerol and fatty acids are the two types of smaller molecules that make up fat.

<h3><u>Saturated fat is found in:</u></h3>

cakes

sausages
cheese
butter

<h3><u>Examples of unsaturated fats:- </u></h3>

Olive
Nuts(almonds, hazelnuts)
Seeds(pumpkin and sesame seeds)

hope it helps...

6 0

3 years ago

The following reaction shows the products when sulfuric acid and aluminum hydroxide react.

scoray [572]

Leftover: approximately 11.73 g of sulfuric acid.

<h3>Explanation</h3>

Which reactant is <em>in excess</em>?

The theoretical yield of water from Al(OH)₃ is lower than that from H₂SO₄. As a result,

Al(OH)₃ is the limiting reactant.
H₂SO₄ is in excess.

How many <em>moles</em> of H₂SO₄ is consumed?

Balanced equation:

2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O

Each mole of Al(OH)₃ corresponds to 3/2 moles of H₂SO4. The formula mass of Al(OH)₃ is 78.003 g/mol. There are 15 / 78.003 = 0.19230 moles of Al(OH)₃ in the five grams of Al(OH)₃ available. Al(OH)₃ is in excess, meaning that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.

How many <em>grams</em> of H₂SO₄ is consumed?

The molar mass of H₂SO₄ is 98.076 g.mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.076 = 28.289 g.

How many <em>grams</em> of H₂SO₄ is in excess?

40 grams of sulfuric acid H₂SO₄ is available. 28.289 grams is consumed. The remaining 40 - 28.289 = 11.711 g is in excess. That's closest to the first option: 11.73 g of sulfuric acid.

6 0

3 years ago

In the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reas

Alexus [3.1K]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.

8 0

3 years ago

Claim how the ecosystem is changing.

Maslowich

Answer:

The environment Ecosystems are also affected by climate change. Habitats are being modified, the timing of events such as flowering and egg laying are shifting, and species are altering their home ranges. Changes are also occurring to the ocean.

Explanation:

6 0

3 years ago

In this experiment, 0.070 g of caffeine is dissolved in 4.0 ml of water. The caffeine is then extracted from the aqueous solutio

Damm [24]

2.0ml of methylene chloride solution is used each time to extract caffeine from the aqueous solution.

Consider the concentration of caffeine obtained during each individual extraction from the aqueous solution to be C.

The total amount of caffeine obtained during each extraction is calculated as

(Total volume of water used to make up the caffeine aqueous solution) x (concentration of caffeine obtained during each individual extraction from the aqueous solution) + (Volume of methylene chloride added during each extraction x distribution coefficient of caffeine x concentration of caffeine obtained during each individual extraction from the aqueous solution)

Substituting these values we get

The total amount of caffeine obtained during each extraction

= (4.0×C )+ (2.0×4.6 × C)

= 13.2 C

The amount of caffeine remaining in the aqueous solution is calculated as

(Total volume of water used to make up the caffeine aqueous solution) x (concentration of caffeine obtained during each individual extraction from the aqueous solution)

Substituting these values we get

The amount of caffeine remaining in the aqueous solution = 4 × C

The fraction of caffeine remaining in aqueous solution is calculated as

= (The total amount of caffeine obtained during each extraction)/ (The amount of caffeine remaining in the aqueous solution)

=4.0 C/13.2 C

= 1/3.3.

Therefore the fraction of caffeine left in aqueous solution after 3 extractions is =(1/3.3)^3 =0.028

Therefore, the total amount of caffeine extracted

=0.070 × (1-(1/3.3)^3)

= 0.068 g

5 0

3 years ago

Read 2 more answers