D.all of the above is the answer for this question
The Rorschach inkblots and the TAT (Thematic Appreciation Test) both rely on providing the subject with ambiguous visual stimuli and assessing the subject's state of mind using the subject's interpretation of the stimuli.
Both use cards, although not all of the cards are used in the TAT. Moreover, the TAT cards contain sketches, while the Rorschach inkblots contain patterns of ink.
Answer: A
Explanation: We know that f=p*n
f=50*300=15000 Hz = 15kHz.
Have a great day! <3
Answer:
M = 222 fringes
Explanation:
given
λ = 559 n m = 559 × 10⁻⁹ m
radius = 0.026 mm = 0.026 ×10⁻³ m
length of the glass plate = 22.1 ×10⁻² m
using relation
![2t=(m+\dfrac{1}{2})\lambda\ \ (m=0,1,2,3...)\\where\ 0\leq t\leq 2r\\m = \dfrac{2t}{\lambda}-\dfrac{1}{2}](https://tex.z-dn.net/?f=2t%3D%28m%2B%5Cdfrac%7B1%7D%7B2%7D%29%5Clambda%5C%20%5C%20%28m%3D0%2C1%2C2%2C3...%29%5C%5Cwhere%5C%200%5Cleq%20t%5Cleq%202r%5C%5Cm%20%3D%20%5Cdfrac%7B2t%7D%7B%5Clambda%7D-%5Cdfrac%7B1%7D%7B2%7D)
![m_{max} = \dfrac{2\times 2r}{\lambda}-\dfrac{1}{2}\\m_{max} = \dfrac{2\times 2\times 0.026\times 10^{-3}}{559\times 10^{-9}}-\dfrac{1}{2}](https://tex.z-dn.net/?f=m_%7Bmax%7D%20%3D%20%5Cdfrac%7B2%5Ctimes%202r%7D%7B%5Clambda%7D-%5Cdfrac%7B1%7D%7B2%7D%5C%5Cm_%7Bmax%7D%20%3D%20%5Cdfrac%7B2%5Ctimes%202%5Ctimes%200.026%5Ctimes%2010%5E%7B-3%7D%7D%7B559%5Ctimes%2010%5E%7B-9%7D%7D-%5Cdfrac%7B1%7D%7B2%7D)
= 221.79
= 221 (approx.)
hence no of bright fringe
M = m + 1
= 221 +1
M = 222 fringes
The correct answer to the question is : 9375 N.
CALCULATION:
As per the question, the mass of the car m = 1500 Kg.
The diametre of the circular track D = 200 m.
Hence, the radius of the circular path R = ![\frac{D}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BD%7D%7B2%7D)
= ![\frac{200}{2}\ m](https://tex.z-dn.net/?f=%5Cfrac%7B200%7D%7B2%7D%5C%20m)
= 100 m.
The velocity of the truck v = 25 m/s.
When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.
Hence, the force acting on the car is centripetal force.
The magnitude of the centripetal force is calculated as -
Force F = ![\frac{mv^2}{R}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E2%7D%7BR%7D)
= ![\frac{1500\times (25)^2}{100}\ N](https://tex.z-dn.net/?f=%5Cfrac%7B1500%5Ctimes%20%2825%29%5E2%7D%7B100%7D%5C%20N)
= 9375 N. [ANS}
The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.