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yawa3891 [41]
3 years ago
11

Mendeleev arranged the known chemical elements in a table according to increasing

Physics
2 answers:
sladkih [1.3K]3 years ago
8 0
1- mass 2. 3 3. Li2O 4. Of the strong attraction..................
wlad13 [49]3 years ago
6 0
<h3>1. <u>Answer</u>; </h3>

Mass

Mendeleev arranged the known chemical elements in a table according to increasing <u>mass</u>.

<h3><u>Explanation</u>; </h3>
  • <em><u>Mendeleev arranged the elements in rows in order of increasing mass so that elements with similar properties were in the same column. He provided an organizing principle that worked for all off the known elements. </u></em>
  • The close match between Mendeleev’s predictions and the actual properties of new elements showed how useful his periodic table could be. He also left spaces for undiscovered elements in order to place elements with similar properties in the same column.
  • Mendeleev's periodic table was useful because it enabled scientists to predict properties of unknown elements.
<h3>2. <u>Answer; </u></h3>

Atomic mass unit.

One twelfth the mass of a carbon-12 atom is used to define an<em><u> atomic mass unit </u></em>

<h3><u>Explanation</u>; </h3>
  • <em><u>An atomic mass unit (AMU) refers to precisely 1/12 the mass of an atom of carbon-12.</u></em> The carbon-12 atom has six protons and six neutrons in its nucleus. One AMU is the average of the proton rest mass and the neutron rest mass.
  • <em><u>The mass of an atom in atomic mass unit is approximately equal to the sum of the number of protons and neutrons in the nucleus. </u></em>
  • The atomic mass unit expresses the relative masses of various isotopes of elements.  

<h3>3. <u>Answer</u>; </h3>

Five electrons  

A member of the boron family has three valence electrons, while a member of the nitrogen family has<u> five electrons</u>.

<h3><u>Explanation</u>; </h3>
  • The number of valence electrons is the number of electrons in the outermost energy level of an atom.  
  • <em><u>Nitrogen family includes, non-metals, metalloids, and metals. The atoms of these elements in the nitrogen family have a 5 valence electrons. </u></em>The family include elements, phosphorus, bismuth, arsenic and antimony. They form bonds through sharing of electrons.
<h3>4. <u>Answer; </u></h3>

Li2O

<h3><u>Explanation; </u></h3>
  • <em><u>Ionic compounds are compounds that are made up of ions. They are formed as a result of transfer of electrons from one atom to another.</u></em> One atom loses electrons while the other atom gains electrons, resulting to formation of negatively charged ion (anion) and positively charged ion (cation) which join via ionic bond to form an ionic compound.
  • <em><u>Lithium oxide is an example of ionic compound formed from lithium and oxygen atoms. Lithium has a valency of one while oxygen has a valency of two, therefore, the chemical formula of lithium oxide will be Li2O.  </u></em>

<h3>5. <u>Answer</u>; </h3>

Of the strong attractions between polar water molecules

Water has a higher boiling point than expected because <u>of the strong attractions between polar molecules. </u>

<h3><u>Explanation;  </u></h3>
  • Water has a high boiling point because of intermolecular forces of attraction called hydrogen bonds. <u>Hydrogen bonding</u> is a form of dipole-dipole interaction, where a molecule that is partially positive is attracted to another molecule that is partially negative.  
  • <em><u>Hydrogen bond being a powerful intermolecular force, it makes water to have a high boiling point, because they require more energy to break the bond.</u></em>


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Four identical capacitors are connected with a resistor in two different ways. When they are connected as in part a of the drawi
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Answer:

T_2 = 0.592

Explanation:

Given

T_1 = 1.48s

See attachment for connection

Required

Determine the time constant in (b)

First, we calculate the total capacitance (C1) in (a):

The upper two connections are connected serially:

So, we have:

\frac{1}{C_{up}} = \frac{1}{C} + \frac{1}{C}

Take LCM

\frac{1}{C_{up}} = \frac{1+1}{C}

\frac{1}{C_{up}}= \frac{2}{C}

Cross Multiply

C_{up} * 2 = C * 1

C_{up} * 2 = C

Make C_{up} the subject

C_{up} = \frac{1}{2}C

The bottom two are also connected serially.

In other words, the upper and the bottom have the same capacitance.

So, the total (C) is:

C_1 = 2 * C_{up}

C_1 = 2 * \frac{1}{2}C

C_1 = C

The total capacitance in (b) is calculated as:

First, we calculate the parallel capacitance (Cp) is:

C_p = C+C

C_p = 2C

So, the total capacitance (C2) is:

\frac{1}{C_2} = \frac{1}{C_p} + \frac{1}{C} + \frac{1}{C}

\frac{1}{C_2} = \frac{1}{2C} + \frac{1}{C} + \frac{1}{C}

Take LCM

\frac{1}{C_2} = \frac{1 + 2 + 2}{2C}

\frac{1}{C_2} = \frac{5}{2C}

Inverse both sides

C_2 = \frac{2}{5}C

Both (a) and (b) have the same resistance.

So:

We have:

Time constant is directional proportional to capacitance:

So:

T\ \alpha\ C

Convert to equation

T\ =kC

Make k the subject

k = \frac{T}{C}

k = \frac{T_1}{C_1} = \frac{T_2}{C_2}

\frac{T_1}{C_1} = \frac{T_2}{C_2}

Make T2 the subject

T_2 = \frac{T_1 * C_2}{C_1}

Substitute values for T1, C1 and C2

T_2 = \frac{1.48 * \frac{2}{5}C}{C}

T_2 = \frac{1.48 * \frac{2}{5}}{1}

T_2 = \frac{0.592}{1}

T_2 = 0.592

Hence, the time constance of (b) is 0.592 s

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