All categories

3 years ago

How would you find the resistance of a parallel circuit with n identical resistors?

Physics

2 answers:

valentinak56 [21]3 years ago

5 0

9514 1404 393

Answer:

R/n

Explanation:

For a given voltage V across each resistor R, the current is V/R. Since there are n parallel paths, the total current is n(V/R). The effective resistance is ...

Reff = V/I = V/(nV/R)

Reff = R/n

VMariaS [17]3 years ago

3 0

Answer:

write the resistance of one resistor

Explanation:

This is because when resistors are connected in parallel current flows in different directions.

You might be interested in

An object of mass m is moving down an inclined plane that makes an angle they a with the horizontal and has height h. Which of t

Lera25 [3.4K]

The answer should be B. According to the conservation of energy, the energy cannot be created nor destroyed, but it can be transformed. Since the object is moving down, that means its height is decreasing, causing the potential energy decreasing and the kinetic energy increasing to fulfill the conservation law.

4 0

3 years ago

About how far does the S wave travel through Earth in 13 minutes?

Elina [12.6K]

Answer:

Explanation:

6000 km

6 0

3 years ago

Read 2 more answers

Watt-hours is a measure of energy, just like kilowatt-hours. How can you convert this to Joules?

satela [25.4K]

Work with your units:

1 watt-hour = 1 (joule/second) · (hour) = 1 (joule-hour / second)

(1 joule-hour/sec) · (3600 sec/hour) = 3600 joules

So 1 watt-hour = 3,600 joules

3 0

2 years ago

Not in book

umka2103 [35]

Answer:

$x=2.4365\ m$

and

$x=-1.4365\ m$

Explanation:

Given:

first charge, $q_1=5\times 10^{-3}\ C$

second charge, $q_2=3\times 10^{-3}\ C$

position of first charge, $x_1=-2\ m$

position of second charge, $x_2=-1\ m$

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

$E_1=E_2$

since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

$\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}$