Ask question

Ask question

All categories

soldi70 [24.7K]

4 years ago

15

A sequence of pitches occurring one after another is perceived: A. horizontally B. vertically C. texturally D. mechanically

1 answer:

I am Lyosha [343]4 years ago

6 0

Answer:

Option A is correct.

A sequence of pitches occurring one after the other is perceived horizontally.

Explanation:

This question belongs more to the field of music.

Pitch is a perceptual property of sounds that allows their ordering on a frequency-related scale.

A sequence of pitches is called Scales. A scale is a sequence of pitches, usually listed in increasing order, starting at some initial pitch called the tonic.

Although, pitches in single form are perceived in high and low form (vertical format), when pitches are arranged in sequences as scales occurring one after the other, they are perceived horizontally!

You might be interested in

A car of mass 998 kilograms moving in the positive y–axis at a speed of

aksik [14]

The total momentum should come out to be <span>2.0 x 10^4 kilogram meters/second </span>

8 0

3 years ago

Read 2 more answers

Two forces are going in opposite directions each force is 9.

professor190 [17]

Answer:

The net force is zero.

Explanation:

Two opposing and equal forces cancel each other out, giving you a net force of zero.

7 0

3 years ago

Please help me on questions 3 and 6, thank you! :D I'll give brainliest!

Anarel [89]

Answer:

3. if you increase your mass you also increase the gravitational pull

6. Radiant energy doesn't depend on a medium and sound energy is dependent on a medium.

Explanation:

i hope this helps-

4 0

3 years ago

Read 2 more answers

Two forces act on a moving object that has a mass of 27 kg. One has a magnitude of 12 N and points due south, while the other ha

levacccp [35]

0.77 m/s2 directed 35° south of west

net force = (-17,-12)

net force = mass * acceleration

(-17,-12) = 27 * (x-acceleration,y-acceleration)

(x-acceleration,y-acceleration) = (-17/27,-12/27) = (-0.629629629..., -0.444...)

angle of acceleration = tan^-1 (-0.444.../-0.629629...) = 35.21759 degrees below negative x-axis.

magnitude of acceleration = sqrt((-0.629629...)^2 + (-0.444...)^2) = 0.77069 (5dp)

7 0

2 years ago

What is the moment of inertia of an object that rolls without slipping down a 3.5-m- high incline starting from rest, and has a

Daniel [21]

Answer:

I = 0.287 MR²

Explanation:

given,

height of the object = 3.5 m

initial velocity = 0 m/s

final velocity = 7.3 m/s

moment of inertia = ?

Using total conservation of mechanical energy

change in potential energy will be equal to change in KE (rotational) and KE(transnational)

PE = KE(transnational) + KE (rotational)

$mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2$

v = r ω

$mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{Iv^2}{r^2}$

$I = \dfrac{m(2gh - v^2)r^2}{v^2}$

$I = \dfrac{mr^2(2\times 9.8 \times 3.5 - 7.3^2)}{7.3^2}$

$I =mr^2(0.287)$

I = 0.287 MR²

3 0

3 years ago