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soldi70 [24.7K]
3 years ago
15

A sequence of pitches occurring one after another is perceived: A. horizontally B. vertically C. texturally D. mechanically

Physics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

Option A is correct.

A sequence of pitches occurring one after the other is perceived horizontally.

Explanation:

This question belongs more to the field of music.

Pitch is a perceptual property of sounds that allows their ordering on a frequency-related scale.

A sequence of pitches is called Scales. A scale is a sequence of pitches, usually listed in increasing order, starting at some initial pitch called the tonic.

Although, pitches in single form are perceived in high and low form (vertical format), when pitches are arranged in sequences as scales occurring one after the other, they are perceived horizontally!

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An electron is moving the east with a speed of 5.0 × 106 m/s. There is an electric field of
Tanzania [10]

The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

<h3>What is Electric field?</h3>

Electric field is the physical field that surrounds a charge.

<h3>How to find final velocity of the electron when it moves some distance in a certain electric field?</h3>
  • From Newton's second law, the acceleration the electron will be

a=F/m=qE/m

  • where q= charge of electron

E= electric field

m= mass of electron

=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)

=10¹⁵×0.526m/s²

  • The kinematics equation v²=v0²+2a(Δx)
  • where v=final velocity of the electron

v0=initial velocity of the electron =5×10⁶m/s

a=acceleration of the electron =10¹⁵×0.526m/s²

Δx=distance moved by the electron in east direction =1cm=10^-2m

  • Now v^2=(5×10⁶)²+2×10¹⁵×0.526×10^-2

=25×10¹²+10.52×10¹²

=35.52×10¹²

  • Now velocity of electron=5.95×10⁶m/s.

Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

Learn more about electric field here:

brainly.com/question/26199225

#SPJ1

5 0
2 years ago
A car traveling 91 km/h is 280 m behind a truck traveling 76 km/h.
Olegator [25]

Answer:

speed of car = 95 km/h

speed of truck = 75 km/h

relative speed of car with respect to truck = 95 - 75 = 20 km/h

now we will convert it into m/s

now time to cross the truck will be given as

time = 19.8 s

so it will take 19.8 s to cross the truck

Explanation:

6 0
3 years ago
A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follo
cestrela7 [59]

Answer:

13.37 rev/min

Explanation:

acceleration due to gravity (g) = 9.8 m/s², centripetal acceleration (a_c) = 1.8 * g = 1.8 * 9.8 m/s² = 17.64 m/s².

r = 9 m

Centripetal acceleration (a_c) is given by:

a_c=\frac{v^2}{r} \\\\v=\sqrt{a_c*r} \\\\v=\sqrt{17.64\ m/s^2*9\ m}\\\\v=12.6\ m/s

The velocity (v) is given by:

v = ωr;  where ω is the angular velocity

Hence:

ω = v/r = 12.6 / 9

ω = 1.4 rad/s

ω = 2πN

N = ω/2π = 1.4 / 2π

N = 0.2228 rev/s

N = 13.37 rev/min

4 0
2 years ago
Could I get help on this question please . My parents won’t help me /:
vovikov84 [41]

Answer:

Tarzan will be moving at 7.4 m/s.

Explanation:

From the question given above, the following data were obtained:

Height (h) of cliff = 2.8 m

Initial velocity (u) = 0 m/s

Final velocity (v) =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 2.8)

v² = 0 + 54.88

v² = 54.88

Take the square root of both side

v = √54.88

v = 7.4 m/s

Therefore, Tarzan will be moving at 7.4 m/s at the bottom.

3 0
3 years ago
If you kicked your mom <br><br> would she be mad?
vfiekz [6]

Answer:

Yes !

Explanation:

8 0
3 years ago
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