There are 3 thirds in one
Answer:
If there are 10 students taking only chemistry, 9 students taking only physics, and 5 students only taking both chemisty and 16 students are taking neither; I would add 10+9+5+16=40 (total students) and divide 10/40 (25% chemistry) 9/40 (22.5% physics) 5/40 (12.5% both) 16/40 (40% neither)
Step-by-step explanation:
1. Determine a single event with a single outcome.
2. Identify the total number of outcomes that can occur.
3. Divide the number of events by the number of possible outcomes.
8 ( 4 - x ) = 7x + 2
32 - 8x = 7x + 2
-7x -7x
--------------------------
32 - 15x = 2
-32 -32
----------------------------
-15x = -30
/-15 /-15
x = 2.
Answer:
17/20 < 88%
Step-by-step explanation:
17/20 = .85
.85 < .88
17/20 < 88%
