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Mars2501 [29]
3 years ago
5

What is the value of y? Square root of 34 x square root of y = 34

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
I think 5.831 = 34 because the value of 34 square root is 5.841.
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Lines m and n are parallel. The measure of angle 6 is 55 114 57.6 3 What is the measure of angle 1? 1552​
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Answer:

125 degree

Step-by-step explanation:

As m // n, so angle 2 and angle 6 is the same so angle 2 = 55 degree, then angle 1 + angle 2 = 180 degree, so angle 1 = 180 - 55 = 125 degree.

If it is helpful, please give me Brainliest.

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The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
forsale [732]

Answer:

a)

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = 3.37*10^{-2} meters per second squared

b)

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = 2.92*10^{-2} meters per second squared

Step-by-step explanation:

The formula is:

v=\frac{2 \pi R}{T}

Where

v is speed

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T is time

and another formula for centripetal acceleration:

a_c=\frac{4 \pi^{2} R}{T^2}

Now,

a)

at equator, the radius is radius of earth (given), time in seconds is

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THus,

v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97

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Centripetal Acceleration:

a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}

Centripetal Acceleration at Equator = 3.37*10^{-2} meters per second squared

b)

At 30.0° north of the equator:

R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6

Now,

Speed = v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}

Centripetal Acceleration at 30 degrees north of equator = 2.92*10^{-2} meters per second squared

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3 years ago
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Ivanshal [37]

Answer:

20 and 40

Step-by-step explanation:

20 doubled is 40

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in the picture

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