Answer:
Value for K would be too small. Less AgCl would dissolve due to the common ion effect due to the presence of Cl- in the water.
Explanation:
Think of this through the lenses of a shifting problem. Cl- ions are a product in this situation and increasing its concentration would shift the reaction back to the solid AgCl. In this specific case, due to Cl- ions, AgCl would dissolve less to maintain equilibrium and as a result, the concentrations of Ag+ and Cl- ions would be lower than normal making a smaller K value.
Answer:
Mitochondria
Explanation:
Glucose in an energy molecule contained in carbohydrate food substances. The end product of the digestion of carbohydrate is glucose which is broken down to produce energy.
The sequence of breakdown of glucose is as follows; In the first step, 6-carbon glucose is broken down into two molecules of 3-carbon pyruvic acid. This occurs in the cytoplasm of the cell. It is an anaerobic process.
In the second step which occurs in the mitochondrion, each of the molecules of pyruvic acid is now oxidized to carbon dioxide and water and energy is produced in the process.
<span>Every atom and molecule has its own chemical potential energy value since atoms and molecules are attracted to each other. Whenever atoms and molecules form ionic or covalent bonds, their individual potential energies are converted into heat or light energy. The heat or light energy is released as the bonds form. Atoms that form strong bonds have lower potential chemical energy levels and release little heat or light, while atoms that form weak bonds have higher potential chemical energy levels and release a lot of heat or light during the formation of chemical bonds.
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Explanation:
The given compounds are oxyacids and in these compounds more is the electronegativity of the central atom more will be its acidic strength.
This is because more is the electronegativity of the central atom more will be the polarity of OH bond. As a result, the compound can readily lose 
ion.
Also, more is the electronegativity of central atom more will be the stability of conjugate base formed.
Thus, we can conclude that given compounds are arranged in increasing acid strength as follows.
HOI < 
< 
< HOF
