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tigry1 [53]
3 years ago
7

How many atoms of phosphorus are in 8.10 mol of copper(II) phosphate?

Chemistry
1 answer:
Dvinal [7]3 years ago
5 0
Cu3(PO4)2 is the chemical name
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Which is a physical property of a gas?
Alexxandr [17]
Physical property of gas: There are a lot, here are some examples: => Air => Oxygen => Carbon dioxide => Flourine => Phosphine => Argon => Carbon monoxide This examples are all gases and each of these gases has its own physical property. The only thing that they makes them the same are that, they are gas with lesser molecules. Usually gas density is lesser compare to the solid or liquid and most gases has undefined melting point.
7 0
4 years ago
Read 2 more answers
Draw a Lewis structure for [H3O]+. Show all unshared pairs and the formal charges, if any.
Montano1993 [528]

Answer: Formal Charges: Hydrogen = 0 and Oxygen = +1

Unshared Pair of electrons: Hydrogen = 0 and Oxygen = 2

Explanation:

The attachment below shows the Lewis structure and the calculations

3 0
3 years ago
Are nails in a jar with water a chemical change
Digiron [165]
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7 0
3 years ago
If the density of an object is 5.2g/cm3, and it’s volume is 3.7 cm3, what is it’s mass?
lord [1]
Here's the equation you use: Density = mass/volume 

1) 5.2g/cm^3 = m/3.7cm^3 

2) m = 5.2g/cm^3 x 3.7cm^3 

3) m = 19.24g 

You can check the answer by plugging it in 

19.24g/3.7cm^3 
= 5.2g/cm^3
5 0
3 years ago
Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in
Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is  2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\   \frac{m_{S} }{m_{O} }= 2

Let us express it as

SO_{\frac{m_{S} }{m_{O} }} = 2

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\   \frac{m_{S} }{m_{O} }= 1

Let us express it as

SO_2_{\frac{m_{S} }{m_{O} }}= 1

Now, for the ratio of both the above-calculated ratios,

\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}

The required ratio is 2:1

3 0
3 years ago
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