The molecular weight of the substance.
The following will ensure laboratory safety during an experiment;
1) Using tongs to handle a hot beaker: This prevents direct contact with the hot beaker and avoids burns
5) Turning off the hot plate after use: If the hot plate is left on, it could injure anyone who might touch it accidentally
Answer:
<h2>5.11 L</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is

Since we are finding the new volume

From the question we have

We have the final answer as
<h3>5.11 L</h3>
Hope this helps you
Answer:
7.5 moles of CaBr2 are produced
Explanation:
Based on the equation:
2AlBr3 + 3CaO → Al2O3 + 3CaBr2
<em>2 moles of AlBr3 produce 3 moles of CaBr2 if CaO is in excess.</em>
<em />
Using this ratio: 2 moles AlBr3 / 3 moles CaBr2. 5 moles of AlBr3 produce:
5 moles AlBr3 * (3 moles CaBr2 / 2 moles AlBr3) =
<h3>7.5 moles of CaBr2 are produced</h3>
<em />
Answer:
<h3>The answer is 27.80 mL</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass = 87.3 g
density = 3.14 g/mL
We have

We have the final answer as
<h3>27.80 mL</h3>
Hope this helps you