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3 years ago

7

True or false? the formula of a compound that expresses the smallest whole-number ratio of the atoms present is called the empir

ical formula.

1 answer:

galben [10]3 years ago

8 0

The answer is : True

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What should you always do at the end of a lab

Murrr4er [49]

Answer:clean up the area

Explanation:

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2 years ago

Gnoma [55]

What volume of 2.50 m lead ll nitrato

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2 years ago

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Electrons in conductors, like copper wire, are free to roam throughout the metal in the presence of the ions that have released

Scrat [10]

Answer:

<u><em>No, I would not consider a metal to be a plasma because plasma is just another state of matter, and the copper wire is in solid state.</em></u>

Explanation:

Metal is not a state of matter. Metals can be solid or liquid (molten) depending on their melting point and the temperature at which they are.

Plasma is a state of matter, similar to gas, but it is reached only at very high temperatures like in the Sun. The particles in plasma state are not neutral atoms or molecules but negatively charged ions and electrons.

The copper wire is yet a solid, thus it cannot be considered a plasma.

Metals can be in plasma state only if the temperature is too high, like the temperatures in the stars. In fact, the metals in the Sun and other hotter stars are in plasma state.

5 0

3 years ago

Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this

maw [93]

Answer: d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

$2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)$ $\Delta H=+1411.1kJ$

Reversing the reaction, changes the sign of $\Delta H$

$C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$

$\Delta H=-1411.1kJ$

On multiplying the reaction by $\frac{1}{2}$ , enthalpy gets half:

$0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)$ $\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol$

Thus the enthalpy change for the given reaction is -705.55kJ

7 0

3 years ago

A 0.98 gram sample of a volatile liquid was heated to 348 k. the gas occupied 265 ml of space at a pressure of 0.95 atm. what is

arlik [135]

Answer:

The molecular weight is $Z = 111.2 \ g/mol$

Explanation:

From the question we are told that

The mass of the sample is $m = 0.98 \ g$

The temperature is $T = 348 K$

The volume which the gas occupied is $V = 265 \ ml = 265 *10^{-3} L$

The pressure is $P = 0.95 \ atm$

Generally from the ideal gas equation we have that

$PV = n RT$

Here n is the number of moles of the gas while the R is the gas constant with value $R = 0.0821 \ atm \cdot L \cdot mol^{-1} \cdot K^{-1}$

$n = \frac{PV}{ RT}$

=> $n = \frac{ 0.95 * 265 *10^{-3} }{ 0.0821 * 348}$

=> $n = 0.00881 \ mol$

Generally the molecular weight is mathematically represented as

$Z = \frac{m}{n}$

=> $Z = \frac{0.98 }{0.00881}$

=> $Z = 111.2 \ g/mol$

8 0

3 years ago