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GalinKa [24]
3 years ago
6

A chemical property of oxygen is that it ____

Chemistry
2 answers:
Andru [333]3 years ago
5 0

Answer:

the answer you are searching for is

AlexFokin [52]3 years ago
4 0
It’s B combines.....
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What quantity is measured in mol/dm³?
natima [27]
L
M =  \frac{n}{V}  \\ M = \frac{mol}{L}  \\ or \\ M =  \frac{mol}{ {dm}^{3} }
mol/dm³ is measure for molarity
3 0
3 years ago
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

15,066.8 J=C\times 2.053^oC

C=7,338.92 J/^oC

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
3 years ago
What needs to be considered in balancing redox reactions?
Degger [83]
Number D both H and OH ions
8 0
3 years ago
Which of the following is/are part of the nitrogen cycle?
Pachacha [2.7K]
Denitrification is part of the nitrogen cycle 
7 0
3 years ago
A teacher is preparing the materials list for an activity that all 6th graders will
Greeley [361]

Answer:

There are 1000 mg in 1. g

There are 1000 g in 1 kg

Each students needs 2,250 mg of clay

Explanation:

In order to determine the amount of how many kilograms to order, the teacher will need to find out the total mass of clay required by the students and then the teacher will have to convert the total mass to the units required for the purchase.

The teacher would have to find out how many milligrams make one kilogram as follows

1 kg = 1000 g

1 g = 1000 mg

Therefore, 2,250 mg = 2250/1000 g = 2.25 g

2.25 g = 2.25/1000 kg = 0.00225 kg.

7 0
3 years ago
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