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2 years ago

A reaction begins with 1.00 mol of HCl in a 4.00 liter container at a certain temperature.

Chemistry

1 answer:

lubasha [3.4K]2 years ago

3 0

Answer:

$[HCl]_{eq}=0.05M$

Explanation:

Hello,

In this case, for the given chemical reaction, the law of mass action at equilibrium results:

$Kc=\frac{[H_2]_{eq}[Cl_2]_{eq}}{[HCl]^2_{eq}}$

Next, in terms of the change $x$ due to reaction extent, it is rewritten, considering an initial concentration of HCl of 0.25M (1mol/4L), as:

$4.00=\frac{(x)(x)}{(0.25-2x)^2}$

Thus, solving for $x$ via quadratic equation or solver, the following results are obtained:

$x_1=0.1M\\x_2=0.17M$

Clearly, the solution is $x=0.1M$ as the other result will provide a negative concentration for the hydrochloric acid at equilibrium, thereby, its equilibrium concentration turns out:

$[HCl]_{eq}=0.25M-2*0.1M$

$[HCl]_{eq}=0.05M$

Best regards.

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Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:

rusak2 [61]

Answer:

60.42% is the percent yield of the reaction.

Explanation:

Moles of methane gas at 734 Torr and a temperature of 25 °C.

Volume of methane gas = V = 26.0 L

Pressure of the methane gas = P = 734 Torr = 0.9542 atm

Temperature of the methane gas = T = 25 °C = 298.15 K

Moles of methane gas = n

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9542 atm\times 26.0L}{0.0821 atm L/mol K\times 298.15 K}=1.0135 mol$

Moles of water vapors at 700 Torr and a temperature of 125 °C.

Volume of water vapor = V' = 23.0 L

Pressure of water vapor = P' = 700 Torr = 0.9100 atm

Temperature of water vapor = T' = 125 °C = 398.15 K

Moles of water vapor gas = n'

$P'V'=n'RT'$

$n'=\frac{PV}{RT}=\frac{0.9100 atm\times 23.0L}{0.0821 atm L/mol K\times 398.15 K}=0.6402 mol$

$CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)$

According to reaction , 1 mol of methane reacts with 1 mol of water vapor. As we can see that moles of water vapors are in lessor amount which means it is a limiting reagent and formation of hydrogen gas will depend upon moles of water vapors.

According to reaction 1 mol of water vapor gives 3 moles of hydrogen gas.

Then 0.6402 moles of water vapor will give:

$\frac{3}{1}\times 0.6402 mol=1.9208 mol$ of hydrogen gas

Moles of hydrogen gas obtained theoretically = 1.9208 mol

The reaction produces 26.0 L of hydrogen gas measured at STP.

At STP, 1 mole of gas occupies 22.4 L of volume.

Then 26 L of volume of gas will be occupied by:

$\frac{1}{22.4 L}\times 26 L= 1.1607 mol$

Moles of hydrogen gas obtained experimentally = 1.1607 mol

Percentage yield of hydrogen gas of the reaction:

$\frac{Experimental}{Theoretical}\times 100$

$\%=\frac{ 1.1607 mol}{1.9208 mol}\times 100=60.42\%$

60.42% is the percent yield of the reaction.

8 0

3 years ago

2. what volume of 0.0150-m hcl solution is required to titrate 150. ml of a 0.0100-m ca(oh)2 solution? (10 points)

laila [671]

100ml volume of 0.0150m hcl solution is requires to titrate 150ml of a 0.0100m caoh2 solution.

Dilution is a solution of decreasing the concentration of a solute in the solution by adding more solvent to the solution. We can use the expression for dilute formula,

C1 V1 =C2 V2

where C1 is the initial concentration,C2 is the final concentration,V1 is the initial volume and V2 is the final volume. Here given, volume of 0.0150M(C1) HCL solution is required to titrate 150ml(V2) of a 0.0100M(C1) Caoh2 solution.

While diluting a solution from a high concentration substance to a low concentration substance we always use the formula of dilution.so, putting all value give in the expression we get the volume of the final concentration.

V1= C2 V2/ C1

= 0.0100m . 150ml /0.0150M

= 100ml

The volume of the hcl solution is 100ml.

To learn more about dilution formula please visit:

brainly.com/question/7208939

#SPJ4

3 0

1 year ago

1. The diagram above shows the repeating groups of atoms that make up two samples. Will the

serious [3.7K]

Answer:

Will likely be the same

Explanation:

We can see in both pictures there is a black molecule and a red molecule. However, we also have a purple molecule in one image and a yellow in the other. It would LIKELY be the same because we have more of the same molecules then more different molecules. Hope this helps

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3 years ago