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3 years ago

A reaction begins with 1.00 mol of HCl in a 4.00 liter container at a certain temperature.

Chemistry

1 answer:

lubasha [3.4K]3 years ago

3 0

Answer:

$[HCl]_{eq}=0.05M$

Explanation:

Hello,

In this case, for the given chemical reaction, the law of mass action at equilibrium results:

$Kc=\frac{[H_2]_{eq}[Cl_2]_{eq}}{[HCl]^2_{eq}}$

Next, in terms of the change $x$ due to reaction extent, it is rewritten, considering an initial concentration of HCl of 0.25M (1mol/4L), as:

$4.00=\frac{(x)(x)}{(0.25-2x)^2}$

Thus, solving for $x$ via quadratic equation or solver, the following results are obtained:

$x_1=0.1M\\x_2=0.17M$

Clearly, the solution is $x=0.1M$ as the other result will provide a negative concentration for the hydrochloric acid at equilibrium, thereby, its equilibrium concentration turns out:

$[HCl]_{eq}=0.25M-2*0.1M$

$[HCl]_{eq}=0.05M$

Best regards.

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3 years ago

An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

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Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

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$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

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4 years ago

According to valence bond theory, which orbitals overlap in the formation of the bond in HCl?

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A) 1s on H and 3p on Cl

In HCl, the H atom has only one valance electron. Each share an electron an therefore a single covalent bond is formed between the two. The bond in HCl is therefore a result of an overlap between 1s orbital and ONLY ONE of the lobes of the 3p orbital of Chlorine.

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What data do you need to determine the specific heat capacity of a substance?

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C is the specific heat capacity

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2 years ago

A student wants to examine a substance by altering the bonds within its molecules. Which of the following properties of the subs

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Question is incomplete, the complete question is as follows:

A student wants to examine a substance by altering the bonds within its molecules. Which of the following properties of the substance should the student examine?

A. Toxicity, because it can be observed by altering the state of the substance

B. Boiling point, because it can be observed by altering the state of the substance

C. Toxicity, because it can be observed by replacing the atoms of the substance with new atoms

D. Boiling point, because it can be observed by replacing the atoms of the substance with new atoms

Answer:

Explanation:

A student can examine a substance without altering the bonds within the molecules by examining its boiling point.

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Hence, the correct answer is "B".

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4 years ago