What is 53.435 to the nearest whole number?

Mathematics

1 answer:

Leni [432]3 years ago

6 0

53

when the first decimal number is 4 or below, then you leave the whole number as it is, and get rid of the decimals.

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I need help i dont understand this

mel-nik [20]

140 tickets sold at the door

Step by Step Explanation:

x = tickets sold in advance
y = tickets sold at the door

We use the formula ax+by=c and a+b=c

x + y = 514
17x + 20y = 9158

y = 514 - x
17x + 20(514 - x)
17x + 10,280 - 20x = 9,158
-3x + 10,280 = 9,158
-3x = -11222
x = 374

This is for tickets sold in advance so we need to find y

374 + y = 514
y = 140

140 tickets were sold at the door

8 0

3 years ago

What is QR ? Enter your answer in the box. units

Dimas [21]

TR = 6
QR = 2(TR)
QR = 2(6)
QR = 12

6 0

3 years ago

Read 2 more answers

Factor: (m+2)^2−(m+2)+mn·(n+2)+2n(n+2)

bazaltina [42]

ANSWER
${(m + 2)}( {n}^{2} + 2n + m + 1)$

EXPLANATION

The given expression is

${(m + 2)}^{2} - (m + 2) + mn(n + 2) + 2n(n + 2)$

We factor to get,

$= {(m + 2)}(m + 2 - 1) +n (n + 2) (m+ 2)$

This implies that,

$= {(m + 2)}(m + 1) +n (n + 2) (m+ 2)$

We factor further to obtain,

$= {(m + 2)}((m + 1) +n (n + 2))$

or

$= {(m + 2)}( {n}^{2} + 2n + m + 1)$

5 0

3 years ago

" A projectile is launched in the air according to the equation h(t)= -16t^2 + 125t + 5. At what time does the projectile land?"

Vlad1618 [11]

"according to the equation is a sloppy description, and announces that whoever said it or wrote it doesn't really have a clue to what the equation means or what it's good for.

h (t) is the HEIGHT of the projectile above the ground at any time 't'. When the projectile hits the ground, h (t) is zero. Write that ! Then you have a quadratic equation that you can easily solve for 't'.

8 0

3 years ago

A restaurant wishes to have at least one server for every 12 tables. Each of the tables in the restaurant seats four guests. If

Fiesta28 [93]

X = number of servers
y = number of guests

$\text {number of guest per table = } 4$ 

 $\text {number of tables = } \dfrac{y}{4}$

 $\text {number of servers needed = } \dfrac{y}{4} \div 12$ 

 $\text {number of servers needed = } \dfrac{y}{4} \times \dfrac{1}{12}$

$\text {number of servers needed = } \dfrac{y}{48}$

There must be at least 1 server for every 12 tables:
$x \geq \dfrac{y}{48}$

8 0

3 years ago