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REY [17]
3 years ago
10

Laura has two large cylindrical barrels of solution in her chemical laboratory. The first barrel contains 900 liters of solution

, and the second barrel contains 100 liters of solution.
Laura drains the first barrel at a rate of 36 liters per minute.

Laura fills the second barrel at a rate of 44 liters per minute.

Which inequality represents the minutes, m, when the second barrel contains a greater or equal amount of solution than the first barrel?
Mathematics
1 answer:
aleksley [76]3 years ago
6 0

Answer:

-36m + 900 < 44m + 100

Step-by-step explanation:

Given that:

The first barrel contains 900 liters of the solution; &

The second barrel contains 100 liters of solution.

So, Laura drains the first barrel at the rate of 36 liters/ min

Since Laura is draining the solution in the first barrel;

Then; we have - 36m + 900 litres

Also; Laura fills the second barrel at a rate of 44 liters per minute.

Since Laura is filling the barrel; we have: 44m + 100

Therefore; the inequality representing when the second barrel contains a greater or equal amount of solution than the first barrel can be expressed as:

- 36m + 900 < 44m + 100

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Step-by-step explanation:

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Nataly_w [17]

Answer:

Required logarithmic function is :

f\left(x\right)=\log_3\left(x\right)

Step-by-step explanation:

We have been fiven that table for the logarithmic function is:

x f(x)

9 2

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81 4

which can be rewritten as:

x f(x)

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3^4 4

Which are basically powers of 3

So we can use logarithmic function as

\log_3\left(9\right)=\log_3\left(3^2\right)=2\log_3\left(3\right)=2(1)=2

Hence required logarithmic function is :

f\left(x\right)=\log_3\left(x\right)

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Answer:

Step-by-step explanation:

Domain x^2 - 9 {Solution: - infinity < x < infinity}

Interval notation (- infinity, infinity)

Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)

Interval notation (-9, infinity)

Axis interception points of x^2 - 9:

X- intercepts (3, 0) (-3, 0)

Y-intercepts (0, -9)

Vertex of x^2 - 9: Minimum (0, -9)

Solve for f:

f (x) = x^2 - 9

Step 1: Divide both sides by x.

fx / x = x^2 - 9 / x

f = x^2 - 9 / x

Answer:

f = x^2 - 9 / x

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