Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1
f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10
The maximum number of roots to a polynomial of order n is n roots. Take the example of a quadratic (order 2) which can intersect the x-axis a maximum of 2 times, and similarly a cubic (order 3) 3 times maximum.
Hence for 8 intersections, minimum order = 8
<h3>
Answer:</h3>
1
<h3>
Step-by-step explanation:</h3>
The given angle is opposite the longest given side, so there will be exactly one solution.
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The number of solutions may be 0, 1, or 2 when the given angle is opposite the shortest given side.
Answer:
Step-by-step explanation:
x²+x²=14²
2x²=196
x²=196/2=98
x=7√2 ft