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dlinn [17]
2 years ago
8

An inverse variation function has a k value of 8. Which ordered pair is on the graph of the function?

Mathematics
1 answer:
Vinvika [58]2 years ago
7 0

The points on the graph of the inverse variation are of the form:

(x, 8/x)

<h3>Which ordered pairs are on the graph of the function?</h3>

An inverse variation function is written as:

y = k/x.

Here we know that k = 8.

y = 8/x

Then the points (x, y) on the graph of the function are of the form:

(x, 8/x).

So evaluating in different values of x, we can get different points on the graph:

  • if x = 1, the point is (1, 8)
  • if x = 2, the point is (2, 4)
  • if x = 3, the point is (3, 8/3)
  • if x = 4, the point is (4, 2)

And so on.

If you want to learn more about inverse variations:

brainly.com/question/6499629

#SPJ1

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Step-by-step explanation:

The negative in front of the 2 made the function flip over the y-axis. While the 2, compressed the function a little, making it so the function touched 2, vertically.

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3 0
2 years ago
Find the coordinates of P so that P partitions AB in the ratio 3:4 with A(-9,-9) and B(5,-2).
ivolga24 [154]

The coordinates of point P are (-3 , -6)

Step-by-step explanation:

If point (x , y) partitions line AB where A = (x_{1},y_{1}) and B = (x_{2},y_{2})

at a ratio m_{1}:m_{2} from A then:

1. x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}

2. y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ P partitions AB in the ratio 3 : 4

∴ m_{1}:m_{2} = 3 : 4

∵ A = (-9 , -9) and B = (5 , -2)

- Substitute the coordinates of points A and B in the rules above

∵ x=\frac{(-9)(4)+(5)(3)}{3+4}

∴ x=\frac{-36+15}{7}

∴ x=\frac{-21}{7}

∴ x = -3

The x-coordinate of P is -3

∵ y=\frac{(-9)(4)+(-2)(3)}{3+4}

∴ y=\frac{-36+(-6)}{7}

∴ y=\frac{-42}{7}

∴ y = -6

The y-coordinate of P is -6

The coordinates of point P are (-3 , -6)

Learn more:

You can learn more about the mid-point of a segment in brainly.com/question/5223123

#LearnwithBrainly

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3 years ago
1000^m/100^n=10^zexpress z in terms of m and n
Hitman42 [59]

\dfrac{1000^m}{100^n}=10^z\\\\\dfrac{10^{3m}}{10^{2n}}=10^z\\\\10^{3m-2n}=10^z\\\\\boxed{z=3m-2n}

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3 years ago
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