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4 years ago

14

When chasing a hare along a flat stretch of ground, a greyhound leaps into the air at a speed of , at an angle of above the hori

zontal. (a) what is the range of his leap and (b) for how much time is he in the air?

1 answer:

Nadusha1986 [10]4 years ago

6 0

The equations for this projectile motion is written in the picture attached.

a.) For this part, you use the last equation. In here, you will need the initial velocity and the launch angle. There seems to be missing information about that. Let's just suppose that the initial velocity is 5 m/s and the launch angle is 30° above the horizontal.

R = (5 m/s)²(sin2*30°)/9.81 m/s² = <em>2.207 m</em>

b.) You use the first equation for this part.

t = 2(5 m/s)(sin 30°)/9.81 m/s² =<em> 0.51 seconds</em>

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Where:

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$m_{2}$ - Mass of the second skater, in kilograms.

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$v_{1}$ - Final velocity of the first skater, in meters per second.

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By (2):

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$v_{2} = \frac{m_{b}\cdot v_{b}}{m_{2}+m_{b}}$

$v_{2} = \frac{(0.043\,kg)\cdot \left(32\,\frac{m}{s} \right)}{58.5\,kg + 0.043\,kg}$

$v_{2} = 0.024\,\frac{m}{s}$

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