a increase in the velocity by 8ms increase every second the math is you take the base velocity usually 0 but in this case 25 and subtract that by the top velocity which is 49 and then divide by the time of increase which is 3 so your answer is 8ms increase per second
Because in Bohr’s model for hydrogen atom we consider only Coulombic interactions between one proton and one electron.
It cannot be extended for other atomic species containing more than one electron. Because in this case in addition to the interaction between nucleus and electron there arises the interactions between electron and electron of the same species. Bohr couldn't solve this problem and this problems are successfully explained on the basis of later developed quantum mechanics.o
Thermal energy is converted to chemical energy.
Answer: 1.8 g
Explanation:
We start first, by calculating the amount of Helium
n = m/M
m = mass of Helium
M = molar mass if Helium
n = 2/4 = 0.5 moles
proceeding further, we use ideal gas law. PV = nRT
Then we have
P1V1/n1T1 = P2V2/n2T2
So that,
n2 = n1T1P2V2/P1V1T2
From the question, we know that, P1 = P2, and T1 = T2. So that,
n2 = n1v2/v1
n2 = (0.5 * 3.9) / 2
n2 = 1.95/2
n2 = 0.975 moles. With this, we can determine the mass, m2 of Helium
n = m/M
m = n * M
m = 0.975 * 3.9
m = 3.8
The difference between both masses are 3.8 - 2 = 1.8 g
Thus, 1.8 g of Helium was added to the cylinder