Answer:
The answer should be (7, 5)
Option D:
is positive product.
Solution:
<em>If the negative sign is in even number of times then the product is positive.</em>
<em>If the negative sign is in odd number of times then the product is negative.</em>
To find which product is positive:
Option A:

Here, number of negative signs = 3
3 is an odd number.
So, the product is negative.
Option B:

Here, number of negative signs = 3
3 is an odd number.
So, the product is negative.
Option C:

Here, number of negative sign = 1
1 is an odd number.
So, the product is negative.
Option D:

Here, number of negative sign = 2
2 is an odd number.
So, the product is positive.
Hence option D is the correct answer.
is positive product.
Given:
The two numbers are


To find:
The highest common factor (HCF) of A and B
Solution:
We have,
...(i)

All the factors of A are prime but the factors of B are not prime. So, it can be written as
...(ii)
From (i) and (ii), it is clear that 3 is the only common factor of A and B. So,

Therefore, the highest common factor (HCF) of A and B is 3.