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MArishka [77]
3 years ago
13

A distribution is symmetrical if the tails on both ends of the density curve that represents it are close to identical. True or

false?
Mathematics
1 answer:
sp2606 [1]3 years ago
5 0
False, because <span>normal distribution is a function that represents the distribution of as many random variables as a symmetrical bell-shaped graph.</span>
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Need help with my homework ​
Volgvan

Answer:

\displaystyle y=\frac{16-9x^3}{2x^3 - 3}

\displaystyle y=-\frac{56}{13}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3

Simplify the radical with the cube:

\displaystyle x^3=\frac{3y+16}{2y+9}

Multiply by 2y+9

\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)

Simplify:

\displaystyle x^3(2y+9)=3y+16

Operate the parentheses:

\displaystyle x^3(2y)+x^3(9)=3y+16

\displaystyle 2x^3y+9x^3=3y+16

Subtract 3y and 9x^3:

\displaystyle 2x^3y - 3y=16-9x^3

Factor y out of the left side:

\displaystyle y(2x^3 - 3)=16-9x^3

Divide by 2x^3 - 3:

\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}

ii) To find y when x=2, substitute:

\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}

\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}

\displaystyle y=\frac{16-72}{16- 3}

\displaystyle y=\frac{-56}{13}

\mathbf{\displaystyle y=-\frac{56}{13}}

8 0
3 years ago
Hey i need help with a quick math problem if anyone can help please.
astraxan [27]

Answer:

a

Step-by-step explanation:

8 0
2 years ago
Evaluate the expression.2(y+8)+5x
N76 [4]
2y+18+5x is what I think
4 0
3 years ago
Read 2 more answers
two children, moe and joe, are allowed to select candy from a plate of nine pieces of candy. Moe, being younger, is allowed to c
Ugo [173]
Joe is correct because Moe could choose two pieces but had a nine piece variety where as Joe could only choose from 7 pieces of candy
3 0
3 years ago
a computer and printer a totoal cost $1132 the cost of the computer is three times the cost of the ptinter
zavuch27 [327]
Use a system of equations

C+P=1132
3P=C

Substitute C in first equation as
3P+P=1132
Simplify
4P=1132
Solve
P=1132/4
P=283

NOW SOLVE FOR C SUBSTITUTING P VALUE IN FIRST EQUATION

C+283=1132
C=1132-283
C=849


Printer = 283$
Computer = 849$
3 0
2 years ago
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