PART A)
Impulse is defined as change in momentum
here finally after hitting the wall car comes to rest
So final momentum of the car will be ZERO
Initial momentum of the car is given as
here m = 2000 kg
v = 77 m/s
now we have
so here impulse will be
PART B)
As we know that force of impact is defined as
so here it is ratio of impulse and time
so if we increase the time of impact by 3 times
so the force will be decrease by factor of 1/3
so here force is decreased by 1/3
Answer:
Explanation:
Given that the force of the particle is,
Now it can be further written as
Now the initial conditions are v=1 at t=0.
So,
Now the velocity will become.
And,
And, another initial condition is x=0 at t=0
Now,
Answer:
176.44 m
Explanation:
y = (vertical vi)t + (1/2)gt^2
315 = 0 + (1/2)(9.8)t^2
t = 8.02s
x = (horizontal vi)t + (1/2)at^2
x = (22)(8.02) + 0
x = 176.44 m
If he wants to increase power, force must increase and decrease time.