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Whitepunk [10]
2 years ago
14

Throw a rock horizontally at 22 m/s from a 315 m tall building. How far from the base of the building will it land?​

Physics
1 answer:
creativ13 [48]2 years ago
6 0

Answer:

176.44 m

Explanation:

y = (vertical vi)t + (1/2)gt^2

315 = 0 + (1/2)(9.8)t^2

t = 8.02s

x = (horizontal vi)t + (1/2)at^2

x = (22)(8.02) + 0

x = 176.44 m

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Answer:

32 cm

Explanation:

f = focal length of the converging lens = 16 cm

Since the lens produce the image with same size as object, magnification is given as

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p = distance of the object from the lens

q = distance of the image from the lens

magnification is given as

m = - q/p

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q = p                                    eq-1

Using the lens equation, we get

1/p + 1/q = 1/f

using eq-1

1/p + 1/p = 1/16

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