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strojnjashka [21]
2 years ago
13

A pickup truck is carrying a load of gravel. The driver hits a bump and gravel falls out, so that the mass if the truck is one h

alf as large after hitting the bump. If the net force on the truck does not change, how does the truck's acceleration change?
Physics
2 answers:
Serjik [45]2 years ago
7 0

Answer:

Earth's gravity would increase with the increase in Earth's mass. The driver hits a bump and the gravel falls out, so that the mass of the truck is one half as large after hitting the bump.

Explanation:

Zinaida [17]2 years ago
5 0

Answer:

Earth's gravity would increase with the increase in Earth's mass. The driver hits a bump and the gravell falls out, so that the mass of the truck is one half as large after hitting the bump.

Explanation:

hope this helps :)❤️

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Shtirlitz [24]

Answer:

Increase

Explanation:

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larisa86 [58]
<span>4.5 m/s This is an exercise in centripetal force. The formula is F = mv^2/r where m = mass v = velocity r = radius Now to add a little extra twist to the fun, we're swinging in a vertical plane so gravity comes into effect. At the bottom of the swing, the force experienced is the F above plus the acceleration due to gravity, and at the top of the swing, the force experienced is the F above minus the acceleration due to gravity. I will assume you're capable of changing the velocity of the ball quickly so you don't break the string at the bottom of the loop. Let's determine the force we get from gravity. 0.34 kg * 9.8 m/s^2 = 3.332 kg m/s^2 = 3.332 N Since we're getting some help from gravity, the force that will break the string is 9.9 N + 3.332 N = 13.232 N Plug known values into formula. F = mv^2/r 13.232 kg m/s^2 = 0.34 kg V^2 / 0.52 m 6.88064 kg m^2/s^2 = 0.34 kg V^2 20.23717647 m^2/s^2 = V^2 4.498574938 m/s = V Rounding to 2 significant figures gives 4.5 m/s The actual obtainable velocity is likely to be much lower. You may handle 13.232 N at the top of the swing where gravity is helping to keep you from breaking the string, but at the bottom of the swing, you can only handle 6.568 N where gravity is working against you, making the string easier to break.</span>
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snow_tiger [21]

Answer:

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