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Illusion [34]
3 years ago
9

Solve for x. 6x2−2=13

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0

Answer: x=\±1.58

\frac{6x^2}{6}=\frac{15}{6}\\\\x^2=\frac{15}{6}

Step-by-step explanation:

By the Addition property of equality, you can add 2 yo both sides of the equation:

6x^2-2+2=13+2\\6x^2=15

By the Division property of equality, you can divide both sides of the equation by 6, then:

\frac{6x^2}{6}=\frac{15}{6}\\\\x^2=\frac{15}{6}

Apply square root to both sides of the equation. So, you get:

\sqrt{x^2}=\±\sqrt{\frac{15}{6}}\\\\x=\±1.58

makkiz [27]3 years ago
5 0

Answer:

x = ±sqrt(5/2)

Step-by-step explanation:

6x^2−2=13

Add 2 to each side

6x^2−2+2=13+2

6x^2 = 15

Divide each side by 6

6/6x^2 = 15/6

x^2 = 5/2

Take the square root of each side

sqrt(x^2) = ±sqrt(5/2)

x = ±sqrt(5/2)

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Applying the Procedure
Verizon [17]

Answer:

15 Square Inches

Step-by-step explanation:

Volume of the cone=40 cubic inches

Height of the cone=8 Inches

<u>Step 1:</u> Applying the formula for the volume of a cone

Volume of a Cone=\frac{1}{3}\pi r^2 h=\frac{1}{3} X $Base Area X Height

<u>Step 2:</u> Substituting values for the variables

40=\frac{1}{3} X $Base Area X 8

<u>Step 3:</u> Simplifying the right side

40=\frac{8}{3} X $Base Area

<u>Step 4:</u> Multiplying by the reciprocal

40X\frac{3}{8}=\frac{8}{3} X\frac{3}{8} X $Base Area\\

<u>Therefore, Base Area of the Cone=15 Square Inches</u>

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8 0
3 years ago
A disk in the shape of a circle has a diameter of 64 millimeters. what is the radius of the disk?
aleksandrvk [35]

Answer:

the radius is 32

Step-by-step explanation:

the radius of a circle is half the diameter

hope this helps

8 0
3 years ago
Read 2 more answers
It’s algebra it says find each function value here is a picture of the work sheet
s344n2d4d5 [400]

1.

8 > 1  so:  a(x) = -4x + 7

a(8) = - 4(8) + 7 = - 32 + 7 = - 25

2.

-6 ≤ 1 ≤ 1   so:   a(x) = 2x - x²

a(1) = 2(1) - (1)² = 2 - 1 = 1

3.

-7 ≤ -6  so:  a(x) = |x - 8|

a(-7) = |-7 - 8| = |-15| = 15

4.

-6 ≤ -3 ≤ 1   so:   a(x) = 2x - x²

a(-3) = 2(-3) - (-3)² = -6 - 9 = - 15

5.

-6 ≤ -¹/₂ ≤ 1   so:   a(x) = 2x - x²

a(-¹/₂) = 2(-¹/₂) - (-¹/₂)² = - 1 - ¹/₄ = - 1¹/₄

6.

⁹/₄ > 1  so:  a(x) = -4x + 7

a(⁹/₄) = - 4(⁹/₄) + 7 = - 9 + 7 = - 2

7 0
3 years ago
Can someone do help with any of these please?
laiz [17]
39.

|z+7|=12/3
|z+7|=4
z+7=4
-(z+7)=4
solve the first equation:
z+7=4
z=-3
solve the second equation:
-(z+7)=4
z=-11

z=-11,-3

8 0
3 years ago
What steps do I take to solve y+2&gt;1/2-2 and the solution
kakasveta [241]
<span>y+2>1/2-2 looks a little strange.  Is it OK to combine the last 2 terms?

</span><span>y+2> -3/2

Then y > -2 - 3/2, or y > -7/2.  y must be greater than -7/2, greater than -3.5.</span>
7 0
3 years ago
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