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Illusion [34]
3 years ago
9

Solve for x. 6x2−2=13

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0

Answer: x=\±1.58

\frac{6x^2}{6}=\frac{15}{6}\\\\x^2=\frac{15}{6}

Step-by-step explanation:

By the Addition property of equality, you can add 2 yo both sides of the equation:

6x^2-2+2=13+2\\6x^2=15

By the Division property of equality, you can divide both sides of the equation by 6, then:

\frac{6x^2}{6}=\frac{15}{6}\\\\x^2=\frac{15}{6}

Apply square root to both sides of the equation. So, you get:

\sqrt{x^2}=\±\sqrt{\frac{15}{6}}\\\\x=\±1.58

makkiz [27]3 years ago
5 0

Answer:

x = ±sqrt(5/2)

Step-by-step explanation:

6x^2−2=13

Add 2 to each side

6x^2−2+2=13+2

6x^2 = 15

Divide each side by 6

6/6x^2 = 15/6

x^2 = 5/2

Take the square root of each side

sqrt(x^2) = ±sqrt(5/2)

x = ±sqrt(5/2)

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Answer: 5n = 3d and 3n + 6 = 2d + 4

Given that the numerator and denominator of a fraction are in the ratio of 3 to 5. When the numerator and denominator are both increased by 2, the fraction is equal to \dfrac{2}{3}.  

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Since n denotes the numerator and m denotes the denominator of the given fraction, so we have:

n/d = 3/5

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Assuming you want to do a cartesian product, then you basically form items (x,y)  such that x is in set A, and y is in set A

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I broke things up into separate rows to show that we can form a 3x3 table. Each row is a different x value from the set {a,b,c}. Each column is a different y value from the set {a,b,c}

In my opinion, this helps organize things much better than rather have it all on one single line like this

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A player tosses a die 6 times.If gets a number 6 Atleast two times he wins 2 dollars ,otherwise he looses 1 dollar.. Find the ex
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Answer:

E(x)=-0.2101

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x_1*p(x_1)+x_2*p(x_2)

Where x_1 and x_2 are the values that the variable can take and p(x_1) and p(x_2) are their respective probabilities.

So, a player can win 2 dollars or looses 1 dollar, it means that x_1 is equal to 2 and x_2 is equal to -1.

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If there are n identical and independent events with a probability p of success and a probability (1-p) of fail, the probability that a events from the n are success are equal to:

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