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Illusion [34]
3 years ago
9

Solve for x. 6x2−2=13

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0

Answer: x=\±1.58

\frac{6x^2}{6}=\frac{15}{6}\\\\x^2=\frac{15}{6}

Step-by-step explanation:

By the Addition property of equality, you can add 2 yo both sides of the equation:

6x^2-2+2=13+2\\6x^2=15

By the Division property of equality, you can divide both sides of the equation by 6, then:

\frac{6x^2}{6}=\frac{15}{6}\\\\x^2=\frac{15}{6}

Apply square root to both sides of the equation. So, you get:

\sqrt{x^2}=\±\sqrt{\frac{15}{6}}\\\\x=\±1.58

makkiz [27]3 years ago
5 0

Answer:

x = ±sqrt(5/2)

Step-by-step explanation:

6x^2−2=13

Add 2 to each side

6x^2−2+2=13+2

6x^2 = 15

Divide each side by 6

6/6x^2 = 15/6

x^2 = 5/2

Take the square root of each side

sqrt(x^2) = ±sqrt(5/2)

x = ±sqrt(5/2)

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91.8 ft

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Step-by-step explanation:

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3 years ago
Solve for x. Enter the solutions from least to greatest. <br> (x+15)^2-10=0
Sergeu [11.5K]

Answer:

  • lesser x = -1.84
  • lesser x = -8.16

Step-by-step explanation:

Given the expression

\left(x+5\right)^2-10=0

Add 10 to both sides

\left(x+5\right)^2-10+10=0+10

Simplify

\left(x+5\right)^2=10

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

solve

x+5=\sqrt{10}

Subtract 5 from both sides

x+5-5=\sqrt{10}-5

x=\sqrt{10}-5

x=-1.8

so

x+5=-\sqrt{10}

Subtract 5 from both sides

x+5-5=-\sqrt{10}-5

Simplify

x=-\sqrt{10}-5

\:x=-8.2

As -1.84 > -8.16

so

  • lesser x = -1.84
  • lesser x = -8.16
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