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3 years ago

6. How many columns are in a 5 x 4 matrix?

Mathematics

1 answer:

bearhunter [10]3 years ago

4 0

The answer is 5 hope that helped even if I’m late

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−3,−8,12,−15,9 find the mean

Jobisdone [24]

Answer:

if any girl want to be my friend?

4 0

3 years ago

Read 2 more answers

Consider generating length-7 strings of lowercase letters. How many strings are there that either begin with 2 consonants or end

Semmy [17]

Answer:

5259544316

Step-by-step explanation:

Given that:

Length of string = 7

Either begins with 2 consonants or ends with 2 vowels :

Either or :

A U B = A + B - (AnB)

Number of vowels in alphabet = 5

Number of consonants = 21

2 consonants at beginning :

First 2 consonants, then the rest could be any:

21 * 21 * 26 * 26 * 26 * 26 * 26 = 5239686816

3 vowels at the end :

First 4 letters could be any alphabet ; last 3 should be vowels.:

26 * 26 * 26 * 26 * 5 * 5 * 5 = 57122000

2 consonants at beginning and 3 vowels at the end :

21 * 21 * 26 *26 *5* 5 * 5 = 37264500

Hence,

2 consonants at beginning + 3 vowels at end 2 consonants at beginning - 2 consonants at beginning and 3 vowels At end

(5239686816 + 57122000) - 37264500

= 5259544316

Hence, number of 7 alphabet strings that begins with 2 consonants and end with 3 vowels = 5259544316

7 0

3 years ago

A spinner with 10 equally sized slices is shown below. (3 slices are blue, 2 are yellow, and 5 are rec the probability that the

Ainat [17]

Answer:

1/2

Step-by-step explanation:

Blue + yellow = 3 + 2 = 5 out of 10 slices

5 out of 10 = 5/10 = 1/2

5 0

2 years ago

3 to the third power minus 2 times 3 plus 5

Dahasolnce [82]

Answer: 26

Step 1

$27-(2)(3)+5$

Step 2

$27-6+5$

Step 3

$21+5$

5 0

3 years ago

Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds

svetlana [45]

Answer:

Yes, but it is not linear. It is exponential : $f(x) = 5\cdot 2^{x-1}$

Step-by-step explanation:

On the first day we have 5 bacteria.

On the second day we will have 5*2 = 10 bacteria.

On the third day we will have 10*2 = 5*2*2 = 5*2^2 = 20 bacteria.

On the fourth day we will have 20*2 = 5*2*2*2 = 5*2^3 = 40 bacteria.

We can see that

$f(x) = 5\cdot 2^{x-1}$ ,

where x is a number of days and f(x) gives us the number of bacteria.

4 0

3 years ago