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Ivanshal [37]
3 years ago
15

Listed in the Item Bank are key terms and expressions, each of which is associated with one of the columns. Some terms may displ

ay additional information when you click on them. Drag and drop each item into the correct column. The order does not matter.
ITEMBANK:
Animalia


Archaebacteria

Eubacteria

Fungi

Plantae

Protista

Columns:

Prokaryotic Unicellular
---------------------------------




Eukaryotic Multicellular Autotroph
---------------------------------



EukaryoticMulticellular Heterotroph
--------------------------------



Eukaryotic Unicellular/Multicellular Auto/Heterotroph
------------------------------------------------------------------------------------------------

Chemistry
2 answers:
Scrat [10]3 years ago
5 0

This is a question of six kingdoms

a) animalia: They  depend on others for their food thus are heterotrophs,also they are multicellular and eukaryotic

b) plantae: They can synthesize their own food and are thus autotrophs. also they are multicellular and eukaryotic

c) fungi:They are heterotrophs and cannot synthesize their own food. They are generally multicellular and eukaryotic

d)protista: They can synthesize their food and some are also heterotrophs. can be unicellular or multicellular,

e)eubacteria: Free living bacteria

f) archaebacteria: the bacteria which lives in drastic environmental conditions.

The same can be classified as shown in the figure

Elena-2011 [213]3 years ago
4 0

I don't think it is possible.

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I hope this link helps you.

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http://astronomy.swin.edu.au/cosmos/P/Phases

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Ca(OH)2 (s) precipitates when a 1.0 g sample of CaC2(s) is added to 1.0 L of distilled water at room temperature. If a 0.064 g s
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Answer:

D) Ca(OH)₂ will not precipitate because Q <  Ksp

Explanation:

Here we have first a chemical reaction in which Ca(OH)₂  is produced:

CaC₂(s)  + H₂O ⇒ Ca(OH)₂ + C₂H₂

Ca(OH)₂  is slightly soluble, and depending on its concentration it may precipitate out of solution.

The solubility product  constant for Ca(OH)₂  is:

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Ksp = [Ca²⁺][OH⁻]²

and the reaction quotient Q:

Q = [Ca²⁺][OH⁻]²

So by comparing Q with Ksp we will be able to determine if a precipitate will form.

From the stoichiometry of the reaction we know the number of moles of hydroxide produced, and since the volume is 1 L the molarity will also be known.

mol Ca(OH)₂ = mol CaC₂( reacted = 0.064 g / 64 g/mol = 0.001 mol Ca(OH)₂

the concentration of ions will be:

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Now we can calculate the reaction quotient.

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Q < Ksp since 4.0 x 10⁻⁹ < 8.0 x 10⁻⁸

Therefore no precipitate will form.

The answer that matches is option D

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