Atoms are made up of three subatomic particles called protons, neutrons, and electrons.
Protons and neutrons are located in the nucleus.
All protons have a positive charge.
All neutrons have no charge or are neutral.
Electrons orbit around the nucleus and have a negative charge.
In an ionic compound the atoms are linked via ionic bonds. These are formed by the transfer of electrons from one atom to the other. The atom that loses electrons gains a positive charge whereas the atom that accepts electrons gains a negative. This happens in accordance with the octet rule wherein each atom is surrounded by 8 electrons
In the given example:
The valence electron configuration of Iodine (I) = 5s²5p⁵
It needs only one electron to complete its octet.
In the given options:
K = 4s¹
C = 2s²2p²
Cl = 3s²3p⁵
P = 3s²3p³
Thus K can donate its valence electron to Iodine. As a result K, will gain a stable noble gas configuration of argon while iodine would gain an octet. This would also balance the charges as K⁺I⁻ creating a neutral molecule.
Ans: Potassium (K)
Answer:
Sodium has 1 valence electron and bismuth has 83 electrons (5 valence electrons)
Explanation:
Answer:
i) Dilute hydrochloric acid will react with Ammonia to form ammonia salt.
ii) dilute hydrochloric acid will react with soduim hydroxide to form sodium chloride and water
iii) dilute hydrochloric acid will react with calcuim carbonate to form Calcium chloride, Carbon dioxide and water.
Explanation:
CHEMICAL EQUATIONS :
I) HCL + NH3 = NH4Cl
ii) HCL+ NaOH = NaCl + H2O
iii) HCL + CaCo = CaCl2 + CO2 + H2O
Both of you are overlooking a pretty big component of the question...the Group I cation isn't being dissociated into water. We're testing the solubility of the cation when mixed with HCl. And this IS a legitimate question, seeing as our lab manual is the one asking.
<span>By the way, the answer you're looking for is "Because Group I cations have insoluble chlorides". </span>
<span>"In order...to distinguish cation Group I, one adds HCl to a sample. If a Group I cation is present in the sample, a precipitate will form." </span>
