The standard deviation of the data set is 19.3
<h3>How to find the standard deviation of the data set?</h3>
The dataset is given as:
82, 94, 105, 68, 57
Calculate the mean using
Mean = Sum/Count
So, we have
Mean = (82 + 94 + 105 + 68 + 57)/5
Evaluate
Mean = 81.2
The standard deviation is then calculated as:
![\sigma = \sqrt{\frac{\sum (x - \bar x)^2}{n-1}}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7B%5Csum%20%28x%20-%20%5Cbar%20x%29%5E2%7D%7Bn-1%7D%7D)
So, we have:
SD = √[(82 - 81.2)^2 + (94 - 81.2)^2 + (105 - 81.2)^2 + (68 - 81.2)^2 + (57 - 81.2)^2)/5 - 1]
This gives:
SD = √[1490.8/4]
So, we have:
SD = 19.3
Hence, the standard deviation of the data set is 19.3
Read more about standard deviation at
brainly.com/question/4514629
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How many groups of 8 in 56, 64, 8, 24? Also, which multiple of 8 is closest to 66, 53, 33, 1, 18, 45, 27, 82? Plz answer between
azamat
First one : 7, 8, 1, 3
second is : 8, 7, 4, 0, 2, 6, 3, 10
these are the answers if i get the questions correctly.
Suppose that the rate of the second train is x mph
the rate of the first one will be (x+26) mph
the distance covered by the trains will be:
Distance=speed*time
first train will be:
(2 4/5)×(x+26)
=14/5(x+26)
=14/5x+364/5
Second train:
14/3(x)
=14/3x
Given that both trains covered the same distance, then
14/5x+364/5=14/3x
364/5=28/15x
x=39 mph
thus the distance between the town will be:
14/3(39)
=182 miles
He bought 2 20-cent stamps.
That is $0.40.
He spent $4.60 on the other stamps.
He bought x 6-cent stamps, y 10-cent stamps, and z 8-cent stamps.
y + 10 = x
z = 3y
6x + 10y + 8z = 460
6(y + 10) + 10y + 8(3y) = 460
6y + 60 + 10y + 24y = 460
40y + 60 = 460
40y = 400
y = 10
x = y + 10 = 10 + 10 = 20
z = 3y = 3(10) = 30
He bought
20 6-cent stamps
10 10-cent stamps
30 8-cent stamps
2 20-cent stamps
Answer:
B. There is only one value for s
Step-by-step explanation:
I hope this works for u.. :3
Can I have a brainliest plz :))