Could someone help are my answers right

What is the graph of fx =4[1/2]x?

Over [174]

Answer:

im pretty sure it is 2

Step-by-step explanation:

8 0

3 years ago

1

Mariana [72]

Answer:

x = 6

Step-by-step explanation:

∠ DBC + ∠ ABC = ∠ ABD , substitute values

5x - 4 + 8x - 3 = 79

13x + 1 = 79 ( subtract 1 from both sides )

13x = 78 ( divide both sides by 13 )

x = 6

8 0

3 years ago

Sissy wants to enlarge a picture of a princess so that she can put it on the wall in her daughter’s room. What will be the area

alisha [4.7K]

Answer:

= 486 in²

Step-by-step explanation:

Linear scale factor = Image distance/object distance

Therefore; Linear scale factor = OL'/OL

= 54/ 12

= 9/2

Area scale factor is equivalent to the square of linear scale factor

Thus;

Area scale factor = (9/2)²

= 81/4

Hence; 81/4 = Area of larger rectangle/Area of smaller rectangle

Area of the smaller rectangle = 4 ×6 = 24 in²

Therefore;

Area of enlarged or larger pic = 81/4× 24

3 0

2 years ago

Read 2 more answers

Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph

Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

$y=-\frac{7}{4}x+4$

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

$y_1=mx+b$

And the second one, that is perpedicular to the one above:

$y_2=nx+c$

The slope of the second one is the negative inverse of the first one:

$n=-\frac{1}{m}$

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

$\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}$

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line: