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3 years ago

Can you give me equation where x=16

1 answer:

6 0

x = 16 in the following equations:
8 × 2 = x
8 + 8 = x
4 × 4 = x

In the following equations, x = 16:
2x = 32
32 ÷ 2 = x = 16
x + 5 = 21
21 - 5 = x = 16

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Anyone know the answer?

Aleksandr-060686 [28]

I’m pretty sure it’s d but i’m not 100%

5 0

4 years ago

Which values are solutions to the inequality below? Check all that apply.

Ronch [10]

You have to plug them in to see each solution, so the answers that apply would be 65 and 66 all the other answers are less than or equal to 8

3 0

3 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago

BRAINLIEST AND 60 POINTS!!!!!!!

PIT_PIT [208]

Answer:

1. P ( tails) = 1/2

2.P (number greater than 4) = 1/3

3. P (2 die sum to 8) = 5/36

Step-by-step explanation:

A coin only has 2 possibilities, head or tails, and they are equally likely

So the probability of getting a tails is 1/2

P ( tails) = 1/2

A die has the numbers 1,2,3,4,5,6 . There are 2 numbers greater than 4. They are 5 and 6. So there are 2 of the 6 choices that work.

P (number greater than 4) = 2/6 = 1/3

See the dice chart

There are 36 possibilities when you roll the die.

There are 5 that sum to 8

P (2 die sum to 8) = 5/36

7 0

3 years ago

Help! The measure of the exterior angle of the triangle is???

just olya [345]

Answer:

92°

Step-by-step explanation:

The exterior angle is equal to the sum of the 2 opposite interior angles, that is

2x - 2 = x + 45 ( subtract x from both sides )

x - 2 = 45 ( add 2 to both sides )

x = 47

Then

exterior angle = 2x - 2 = 2(47) - 2 = 94 - 2 = 92°

5 0

3 years ago