Answer:
1) The neutralization reaction will mot be completed.
2) pH = 0.6.
Explanation:
<em>1) Will the neutralization reaction be completed?</em>
For the neutralization reaction be completed; The no. of millimoles of the acid must be equal the no. of millimoles of the base.
The no. of millimoles of 125 mL of 2.0 M HCl = MV = (2.0 M)(125.0 mL) = 250.0 mmol.
The no. of millmoles of 175 mL of 1.0 M NaOH = MV = (1.0 M)(175.0 mL) = 175.0 mmol.
∴ HCl will be in excess.
∴ The neutralization reaction will mot be completed.
<em>2) If not what is the pH of the final solution?</em>
[H⁺] =[ (MV)HCl - (MV)NaOH]/V total = (250.0 mmol - 175.0 mmol) / (300.0 mL) = 0.25 M.
∵ pH = - log[H⁺]
<em>∴ pH =</em> - log(0.25) =<em> 0.6.</em>
The detriment of these advancements to the Earth is that: the growing population is taxing Earth's resources which could lead to the extinction of many species.
<h3>The effect of science and technology.</h3>
Various scientific discoveries and technological advances around the world have led to an exponential increase in Earth's population with no end of the growth in sight.
In conclusion, we can infer and logically deduce that the statement which best describes how these advancements are detrimental to the Earth is that the growing population is taxing Earth's resources and this may likely lead to the extinction of many species of organisms.
Read more on species here: brainly.com/question/15971107
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Answer:
900g
Explanation:
Given parameters:
Number of moles of Sc = 20moles
Unknown:
Mass of Sc = ?
Solution:
To find the mass of the scandium given, we use the expression below:
Mass = Number of moles x molar mass
Molar mass of Sc = 45g/mol
So;
Mass of Sc = 20 x 45 = 900g
Explanation:
The group number in the periodic table represents number of valence electrons of the elements in a certain group.
Group 1 : 2,8,1
Group 2 : 2,8,8,2
Group 3 : 2,8,3
Group 4: 2,4
Group 7 : 2,8,7
Answer:
The net ionic equation will be MgCl₂ + 2 NaOH → Mg(OH)₂ + 2 NaCl
Explanation:
Ionization of MgCl₂ is as follows
MgCl₂ → Mg²⁺ + 2 Cl⁻
Ionization of NaOH is as follows
NaOH → Na⁺ + OH⁻
It is a one type of substitution reaction where OH⁻ combined with Mg²⁺ to give magnesium hydroxide .
On the other hand Cl⁻ combined with Na⁺ to give sodium chloride as product.
Using proper stoichiometry to balanced the number of atoms in both side .
