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3 years ago

How does temperatures affect the density of ocean water?

2 answers:

8 0

The correct answer is B. When temperature decreases the cold water is more dense due to molecules being stiffened together.

elena55 [62]3 years ago

8 0

Answer:

As temperatures decrease, molecules move closer together, making cold water more dense than warm water.

Explanation:

As temperatures increase, more energy is available to the molecules, which respond by moving at faster rates.

I took the test and it was right 100% :)

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Consider the two gaseous equilibria: The values of the equilibrium constants K 1 and K 2 are related by

Sauron [17]

The question is missing parts. The complete question is as follows.

Consider the two gaseous equilibria involving SO2 and the corresponding equilibrium constants at 298K:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$ ; $K_{1}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}; K_{2}$

The values of the equilibrium constants are related by:

a) $K_{1}$ = $K_{2}$

b) $K_{2} = K_{1}^{2}$

c) $K_{2} = \frac{1}{K_{1}^{2}}$

d) $K_{2}=\frac{1}{K_{1}}$

Answer: c) $K_{2} = \frac{1}{K_{1}^{2}}$

Explanation: <u>Equilibrium</u> <u>constant</u> is a value in which the rate of the reaction going towards the right is the same rate as the reaction going towards the left. It is represented by letter K and is calculated as:

$K=\frac{[products]^{n}}{[reagents]^{m}}$

The concentration of each product divided by the concentration of each reagent. The indices, m and n, represent the coefficient of each product and each reagent.

The equilibrium constants of each reaction are:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$

$K_{1}=\frac{[SO_{3}]}{[SO_{2}][O_{2}]^{1/2}}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}$

$K_{2}=\frac{[SO_{2}]^{2}[O_{2}]}{[SO_{3}]^{2}}$

Now, analysing each constant, it is easy to see that $K_{1}$ is the inverse of $K_{2}$ .

If you doubled the first reaction, it will have the same coefficients of the second reaction. Since coefficients are "transformed" in power for the constant, the relationship is:

$K_{2}=\frac{1}{K_{1}^{2}}$

8 0

3 years ago

For a reaction:

torisob [31]

Looking at the equation .look at the moles noted below

Ca(OH)_2=1mol
NH_2Cl=2mol.
CaCL_2=1mol
NH_2=2mol
H_20=2mol.

There is 2 moles of NH2Cl.

Hence limiting reagent is Ca(OH)_2

Moles at reactant=3

Moles at product=5

Moles left:-

$\\ \sf\longmapsto 5-3=2mol$

$\\ \sf\longmapsto pV=nRT$

$\\ \sf\longmapsto 1.5V=2(8.3)(27)$

$\\ \sf\longmapsto 1.5V=448.2$

$\\ \sf\longmapsto V=\dfrac{448.2}{1.5}$

$\\ \sf\longmapsto V=298.8mL$

7 0

3 years ago

20 grams of water. She poured out 15 grams. Which of the following physical properties of the water changes?

zlopas [31]

Answer:

Volume only intrinsic

Explanation:

8 0

4 years ago

The density of silicon is 2.33 g/cm 3 . What is the volume of a piece of silicon that has a mass of 83.8 g ?

horrorfan [7]

Density is found by dividing mass over volume:
d=M/V. In this problem, we know the density, and the mass. Solve the general equation for volume, then enter the values from the problem and evaluate:
d=m/v [multiply v to both sides, then divide d from both sides]

v=m/d
v=83.8g/(2.33g/cm³)
v=35.965 cm³
v=36.0 cm³ to three significant figures (since your given information only has 3 sig figs)

5 0

3 years ago

D = 24 g/ml<br> v = 1200 ml<br> m = ?

8_murik_8 [283]

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 24 × 1200

We have the final answer as

Hope this helps you

5 0

3 years ago