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12345 [234]
3 years ago
8

Acetonitrile (ch3c≡n) is deprotonated by very strong bases. part a draw resonance forms to show the stabilization of the carbani

on that results.

Chemistry
1 answer:
natali 33 [55]3 years ago
6 0

Hey there!

Acetonitrile (CH3C≡N  )

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Breathing equipment used by rescue workers needs to capture the CO2 the humans breath out and produce O2 for them to breath in,
const2013 [10]

Answer: 4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for reaction of potassium superoxide  with carbon dioxide to produce oxygen and potassium carbonate will be:

4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2

8 0
2 years ago
Why might people add a base to an acidic lake?
spayn [35]

Answer:

To decrease the algae

Explanation:

Acid lakes have more algae than other lakes

6 0
3 years ago
Is C3HNO an organic molecule
antoniya [11.8K]

Answer:

Yes.

Explanation:

8 0
3 years ago
A buffer is prepared by dissolving honh2 and honh3no3 in some water. write equations to show how this buffer neutralizes added h
Anestetic [448]
Hydroxylamine in water: HONH₂(aq) + H₂O(l) ⇄ HONH₃⁺(aq) + OH⁻(aq).
Hydroxylammonium nitrate in water: HONH₃NO₃(aq) → OHNH₃⁺(aq) + NO₃⁻(aq).
1) with positive hydrogen ions (protons) react base and gives weak conjugate acid: 
H⁺(aq) + HONH₂(aq) ⇄ HONH₃⁺(aq).
2) with hydroxide anions react acid and produce weak base and weak electrolyte water:
HONH₃⁺(aq) + OH⁻(aq) ⇄ HONH₂(aq) + H₂O(l).


8 0
3 years ago
Read 2 more answers
If you start with 13 mole H2O and 50 grams of O2 what is the percent yield of H202 if 100 grams of H202 is actually made?
dmitriy555 [2]

Answer:

94.1 %

Explanation:

We firstly determine the equation:

2H₂O + O₂ →  2H₂O₂

2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.

We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol

Certainly oxygen is the limiting reactant.

2 moles of water react to 1 mol of oxygen.

13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)

As we determine the limiting reactant we continue to the products:

1 mol of O₂ can produce 2 moles of H₂O₂

Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles

We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g

That's the 100% yield or it can be called theoretical yield.

Percent yield = (Yield produced / Theoretical yield) . 100

(100g / 106.25 g) . 100 = 94.1 %

3 0
3 years ago
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