To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:
Let 1 = argon gas 2 = unknown gas
r2 = 0.91r1r1/r2 = 1/0.91
1/0.91 = √M2/M1 = √M2/40M2 = 48.30 g/mol
The answer is D. (2,2,2,1)
Answer:
Chromium is reduced in forward reaction
Explanation:
A species is said to be oxidized if oxidation number of the species increases.
A species is said to be reduced if oxidation number of the species decreases.
Oxidation number of Cr in = +6
Oxidation number of Cr in = +3
So change in oxidation number of Cr in forward reaction = (+3)-(+6) = -3
Hence oxidation number of Cr decreases on going from to .
So, chromium is reduced in forward reaction.
A or D I think...sorry if it’s wrong