1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Allushta [10]
3 years ago
15

Which of these is the best argument for switching from combustion-powered cars to fuel cell cars in order to help the environmen

t?
They use hydrogen, which produces water vapor instead of CO2.
They conserve gasoline reserves so they can be burned in the future.
They decrease the money spent by consumers on transportation.
They decrease the reliance on other countries for non-renewable resources.
Chemistry
1 answer:
Virty [35]3 years ago
7 0
Hello User

Question: <span>Which of these is the best argument for switching from combustion-powered cars to fuel cell cars in order to help the environment?

Answer: </span><span>They use hydrogen, which produces water vapor instead of CO2.

Reason: This is the best argument because it is saying that pollution will go down if you use Combustion powered cars. It relates to any situation and all of the cars do this.

I hope I helped
-Chris</span>
You might be interested in
Which of the following has the greatest mass, in grams? 1 atom of lead (Pb) 0.5 mol silver (Ag) atoms 0.3 mol gold (Au) atoms 25
Strike441 [17]

Answer : Option C) 0.3 mol of Gold.

Explanation : Amongst the options given in the question, 0.3 mol of Au is the greatest in mass in grams.

As 0.3 mol X atomic weight of Au (196.966) = 59.088 grams;

Silver has 0.5 mol X atomic weight of Ag (107.86) = 53.93 grams;

The other options are not relevant as they deal in the atomic range which has mass value very less as compared to the moles of elements.

Therefore, it is clear that Au has the greatest mass amongst the given choices.

8 0
4 years ago
Read 2 more answers
Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 1
mario62 [17]

Answer:

Mass of HCl leftover = 6.4 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NaOH + HCl —> NaCl + H₂O

Next, we shall determine the masses of NaOH and HCl that reacted from the balanced equation. This can be obtained as follow:

Mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mass of NaOH from the balanced equation = 1 × 40 = 40 g

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Mass of HCl from the balanced equation = 1 × 36.5 = 36.5 g

SUMMARY:

From the balanced equation above,

40 g of NaOH reacted with 36.5 g of HCl.

Next, we shall determine the mass of HCl required to react with 7 g of NaOH. This can be obtained as follow:

From the balanced equation above,

40 g of NaOH reacted with 36.5 g of HCl.

Therefore, 7 g of NaOH will react with = (7 × 36.5)/40 = 6.4 g of HCl.

Thus, 6.4 g of HCl is required for the reaction.

Finally, we shall determine the leftover mass of HCl. This can be obtained as follow:

Mass of HCl given = 12.8 g

Mass of HCl that reacted = 6.4 g

Mass of HCl leftover =?

Mass of HCl leftover = (Mass of HCl given) – (Mass of HCl that reacted)

Mass of HCl leftover = 12.8 – 6.4

Mass of HCl leftover = 6.4 g

7 0
3 years ago
Each day one astronaut exhales about 448 L of carbon dioxide. how many grams of LiOH is needed to remvoe this much carboon dioxi
Romashka [77]

Answer:

How to determine the mole of LiOH required to react with 20 moles of CO₂ per day

CO₂ + 2LiOH —> Li₂CO₃ + H₂O

From the balanced equation above,

1 mole of CO₂  required 2 moles of LiOH.

Therefore,

20 moles of CO₂ will require = 20 × 2 = 40 moles of LiOH

How to determine the mole of LiOH required by two astronauts for 3 days

Mole of LiOH for 1 person per day = 40 moles

Mole of LiOH for 2 persons per day = 2 × 40 = 80 moles

Mole of LiOH for 2 persons for 3 days = 80 × 3 = 240 moles

Explanation:

mark brainliest

7 0
2 years ago
N a football game, two players tackle each other so hard that they both fly in opposite directions after they hit each other. �W
evablogger [386]

Answer:

Newton's Third Law

Explanation:

Newton's Third Law stipulates that for every action there is an equal and opposite reaction.

So when the two players are tackling they exert a force on each other.

If player 1 tackles (exerts a force) player 2,  player 2 will exert an equal and opposite reaction on player 1 as stated in Newton's Third Law.

Therefore when they tackle each other so hard they both experience reaction forces so powerful that they fly in opposite directions.

Thus this is an example of the Newton's Third Law.

4 0
3 years ago
What is it about the structure of magnesium atoms that makes them react more slowly than calcium atoms?
vovikov84 [41]
Is there any answer so I can answer it
7 0
3 years ago
Other questions:
  • What is the approximate molar mass of a molecular solute if 300 g of the solute in 1000 g of water causes the solution to have a
    15·2 answers
  • During which part of the scientific method would error bars be used?
    9·1 answer
  • A chemist prepares a solution by adding 293 mgmg of K2Cr2O7K2Cr2O7 (MWMW = 294.19 g/molg/mol ) to a volumetric flask, and then a
    13·1 answer
  • When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
    10·1 answer
  • Read the following chemical equation.
    14·1 answer
  • You want to decaffeinate your coffee by extracting the caffeine out with dichloromethane (they don't do it that way anymore, but
    5·1 answer
  • How many molecules are there in a group that has a mass in grams that is the same
    14·1 answer
  • What is the formula for magnesium combining with chlorine ​
    10·2 answers
  • 4.5cm wide by 5.750cm long by 1.50cm tall what is the volume of the box
    9·1 answer
  • how many moles of oxygen would you need to produce 4 moles of aluminum oxide? 4 Al + 3 O2 ----&gt; 2 Al2O3
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!