Answer:

Step-by-step explanation:
Let A1 be the area of one square and A2 be the area of second square
So,
A1 = s^2
where s is side of square

So side of one square is 
To calculate the length of fence we need to find the perimeter of the square
So,
P1 = 4 * s

For second square:

The perimeter will be:

So the total fence will be: P1+P2

Answer:
0.05 + 0.1y = 0.12 + 0.06y
Step-by-step explanation:
Here, we want to find y which is the heat in which the amount of mercury in each of the water bodies is same.
Now for the first water body:
Initial is 0.05 ppb and after y years, we have a rise of 0.1 * y = 0.1y ppb
So the amount of mercury in ppb after y years would be; 0.05 + 0.1y
For the second water body;
Initial is 0.12 and a rise of 0.06 ppb per year for y years. The rise would be 0.06 * y = 0.06y
So total amount of mercury here is 0.12 + 0.06y
So to find y which is the year the amount of mercury in each water body is same, we simple equate both and that would be;
0.05 + 0.1y = 0.12 + 0.06y
Answer:
(-13/5,0) and (-17/5,0)
Step-by-step explanation:
(-13/5,0) and (-17/5,0) would be the x-intercepts